Answer: The amount invested at 10% was $3200.
Step-by-step explanation:
Since we have given that
Principal amount = $7200
Rate of interest are 10% and 9%.
Total interest = $680
Let the amount invested on 10% be 'x'.
Let the amount invested on 9% be '7200-x'.
According to question, we get that
Hence, the amount invested at 10% was $3200.
Distribution table for the question is attached below :
Answer:
0.533
Step-by-step explanation:
Let :
M = math
D = Drama
Probability that a randomly chosen student takes math or drama ; P(M u D)
Recall:
P(A u B) = p(A) + p(B) - p(A n B)
P(M u D) = p(M) + p(D) - p(M n D)
Probability = required outcome / Total possible outcomes
From the table :
P(M) = 119 / 302
P(D) = 67 / 302
P(M n D) = 25 / 302
Therefore,
P(M u D) = 119/302 + 67/302 - 25/302
P(M u D) = (119 + 67 - 25) / 302
P(M u D) = 161 / 302
P(M u D) = 0.5331125
P(M u D) = 0.533 ( 3 decimal places)
