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2 years ago

Y=2^x+6 domain and range

Mathematics

1 answer:

Readme [11.4K]2 years ago

3 0

Answer:

Find the Domain and Range

Find the domain by finding where the equation is defined. The range is the set of values that correspond with the domain.

Domain:

( − ∞ , ∞ ) , { x | x ∈R }

Range:

( 6 , ∞ ) , { y | y > 6 }

Step-by-step explanation:

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Answer: 3

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3 years ago

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faltersainse [42]

Answer:

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Step-by-step explanation:

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What is 5 less than the product of 10 and c?

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2 years ago

You are situated 300 feet from the base of Tower Glitz Plaza watching an external elevator descend down the side of the building

nordsb [41]

Answer:

18.66 ft/s

Step-by-step explanation:

The distance between you and the elevator is given by:

$h=\sqrt{x^2+y^2}$

The rate of change for the distance between you and the elevator is given by:

$\frac{dh}{dt}=\frac{dh}{dy}*\frac{dy}{dt}$

$-16=\frac{dh}{dy}*\frac{dy}{dt}$

$\frac{dh}{dy}=\frac{d}{dy} (\sqrt{x^2+y^2})\\$

Applying the chain rule:

$u=x^2+y^2\\\frac{dh}{dy}=\frac{d\sqrt u}{du} *\frac{du}{dy}\\\frac{dh}{dy}=\frac{1}{2\sqrt u} *2y\\\frac{dh}{dy}=\frac{y}{\sqrt {(x^2+y^2)}}$

Therefore, at x=300 and y = 500, dy/dt is:

$-16=\frac{y}{\sqrt {(x^2+y^2)}}*\frac{dy}{dt}\\-16=\frac{500}{\sqrt {(300^2+500^2)}}*\frac{dy}{dt}\\\frac{dy}{dt}=-18.66\ ft/s$

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3 years ago

What are the terms, factors, coefficients and constants of the algebraic equation 9 – 12k?

natulia [17]

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3 years ago