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3 years ago

If 2p°and ( p+15)are a pair of complementary angles find them.

Mathematics

1 answer:

Andrej [43]3 years ago

7 0

Answer:

angles r 50°&40°

Step-by-step explanation:

2p+p+15=90°
3p=90°-15°
3p=75°
p=75°/3
p=25°

2p=2×25=50°

p+15=25+15=40°

<h3>stay safe healthy and happy.</h3>

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Step-by-step explanation:

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3 years ago

In the questions below nine people (Ann, Ben, Cal, Dot, Ed, Fran, Gail, Hal, and Ida) are in a room. Five of them stand in a row

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Step-by-step explanation:

Ben is present in all pictures so rest of 4 persons to be selected from 8 persons , no of ways to do it is

⁸C₄ = 8 x 7 x 6 x 5 / 4 x 3 x 2 x 1

= 70 .

In one of these combination , we can get 5 ! ( five factorial )

Total no of permutations

= 70 x 5 !

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b ) Both Ed and Gail are present

The above derivation changes to the following .

Total no of permutations

= ⁷C₃ x 5 !

= 35 x 120

= 4200

c )

exclude 2 person from 9 to be selected

permutation

= ⁷C₅ x 5 !

= 21 x 120

= 2520

d )

rest of 3 person from 7 persons , no of permutations

⁷P₃ = 7 x 6 x 5 = 210

e )

Hal or Ida can occupy any of the 5 position which can be done in 5 ways .

when one position is occupied , the rest of 4 position can be occupied by 7 persons which can be done in

⁷P₄ ways

Total ways = 5 x ⁷P₄

= 5 x 840

= 4200

f )

They can occupy position like 1,2 or 2,3 or 3,4 or 4,5

Rest of the position can be occupied in ⁷P₃ ways

Total ways = 4 x ⁷P₃

= 4 x 210

= 840

They can also be exchanged mutually so no of ways

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g ) No of pictures in which Ann and Ben are present

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Rest of position that can be shuffled = ⁷P₃

Total no of pictures in which both are present

= ⁵P₂ x ⁷P₃

= 20 x 210

= 4200

out of which they will be standing next to each other = 1680

no of pictures in which they will not be standing next to each other

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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

9 (2a + 1)

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4 years ago

Read 2 more answers

If 2p°and ( p+15)are a pair of complementary angles find them.​

If 2p°and ( p+15)are a pair of complementary angles find them.