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3 years ago

I need help with this problem

Mathematics

1 answer:

Amanda [17]3 years ago

5 0

Answer:

Do the Pythagorean theorem

Step-by-step explanation:

4 squared plus 2.9 squared = C squared

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Please help me solve the right triangle. Round decimal answers to the nearest tenth.

aev [14]

Answer:

see below

Step-by-step explanation:

tan theta = opp/ adj

tan S = 45/24 = 15/8

tan R = 24/45 = 8/15

8 0

3 years ago

Read 2 more answers

What!!!?!?! Could someone help me with the first two I don't understand and it's due tomorrow

Delicious77 [7]

If said number is x, that means that twice (2 times) a number and 2x-7=13. Adding 7 to both sides, we get 2x=20 and by dividing both sides by 2 we get x=10. For 2, we see that the sum of a number and 6 is first priority, so we have (x+6)*7=-43. Dividing both sides by 7, we get x+6=-43/7. After that, we subtract both sides by 6 to get -43/7-6=x

3 0

3 years ago

catering service offers 8 appetizers, 11 main courses, and 7 desserts. A banquet committee is to select 7 appetizers, 8 main

guapka [62]

Answer: The required number of ways is 46200.

Step-by-step explanation: Given that a catering service offers 8 appetizers, 11 main courses, and 7 desserts.

A banquet committee is to select 7 appetizers, 8 main courses, and 4 desserts.

We are to find the number of ways in which this can be done.

We know that

From n different things, we can choose r things at a time in $^nC_r$ ways.

So,

the number of ways in which 7 appetizers can be chosen from 8 appetizers is

$n_1=^8C_7=\dfrac{8!}{7!(8-7)!}=\dfrac{8\times7!}{7!\times1}=8,$

the number of ways in which 8 main courses can be chosen from 11 main courses is

$n_2=^{11}C_8=\dfrac{11!}{8!(11-8)!}=\dfrac{11\times10\times9\times8!}{8!\times3\times2\times1}=165$

and the number of ways in which 4 desserts can be chosen from 7 desserts is

$n_3=^7C_4=\dfrac{7!}{4!(7-4)!}=\dfrac{7\times6\times5\times4!}{4!\times3\times2\times1}=35.$

Therefore, the number of ways in which the banquet committee is to select 7 appetizers, 8 main courses, and 4 desserts is given by

$n=n_1\times n_2\times n_3=8\times165\times35=46200.$

Thus, the required number of ways is 46200.

7 0

4 years ago

Andrew and Kate have $30 to spend on dinner tax and gratuity at Moe's restaurant tax is 6% and they will give a 50% tip on the t

kenny6666 [7]

Given the money which the Andrew and Kate have to spend on dinner is $30.
Tax is 6%
Now we have to find the total cost of dinner. If the cost of dinner is less then the money that the Andrew and Kate have then we can say Andrew and Kate have enough money to pay their bill.
Tax rate = 6%
Total tax= (Tax apply)(dinner cost)
= 0.06\times21
= $1.26
Dinner cost after tax is $21+$1.26
=$22.26
Now it is given that they will give 15% tip on the total bill after taxes
∴ Amount of tip given = 15\% \times 22.26
⇒ = $3.339
Total bill of dinner = dinner cost+Tax+Tip
= $22.26+$3.339
= $25.599
Hence total bill of dinner is less than the money the have to spend.
⇒ Andrew and Kate have enough money to pay their bill.

5 0

4 years ago

What is the volume of the cylinder below?

klio [65]

Answer:

$\sf 36\pi \ units^3$