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Tpy6a [65]
3 years ago
9

I need help with this problem

Mathematics
1 answer:
Amanda [17]3 years ago
5 0

Answer:

Do the Pythagorean theorem

Step-by-step explanation:

4 squared plus 2.9 squared = C squared

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1 oz = 0.0625 lbs or 1/16 lbs

1 lb = 16 oz

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What the inequality?
miskamm [114]

Y= Slope(x) + y-int. Y= mx +b Y= -3x +2

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4 years ago
Write the verbal phrase as an algebraic expression. use x for the variable in your expression.
devlian [24]
The answers are
1. x-10
2. x+8
3 0
3 years ago
Recall that in the problem involving compound interest, the balance A for P dollars invested at rate r for t years compounded n
RoseWind [281]

Answer:

(a)∴A=$6753.71.

(b)∴A=$1480.24

(c) ∴P=$7424.70

(d)∴P=$49759.62

(e)∴P=$5040.99

(f) ∴P=$2496.11

Step-by-step explanation:

We use the following formula

A=P(1+\frac rn)^{nt}

A=amount in dollar

P=principal

r=rate of interest

(a)

P=$2,500, r=5%=0.05,t =20 years , n= 4

A=\$2500(1+\frac{0.05}{4})^{(20\times 4)

   =$6753.71

∴A=$6753.71.

(b)

P=$1,000, r=8% =0.08,t =5 years , n= 2

A=\$1000(1+\frac{0.08}{2})^{(5\times 2)

   =$1480.24

∴A=$1480.24

(c)

A=$10,000, r=6% =0.06,t =5 years , n= 4

10000=P(1+\frac{0.06}{4})^{(5\times 4)}

\Rightarrow P=\frac{10000}{(1+0.015)^{20}}

\Rightarrow P=7424.70

∴P=$7424.70

(d)

A=$100,000, r=6% =0.06,t =10 years , n= 12

100000=P(1+\frac{0.07}{12})^{(10\times 12)}

\Rightarrow P=\frac{100000}{(1+\frac{0.07}{12})^{120}}

\Rightarrow P=49759.62

∴P=$49759.62

(e)

A=$100,000, r=10% =0.10,t =30 years , n= 12

100000=P(1+\frac{0.10}{12})^{(30\times 12)}

\Rightarrow P=\frac{100000}{(1+\frac{0.10}{12})^{360}}

\Rightarrow P=5040.99

∴P=$5040.99

(f)

A=$100,000, r=7% =0.07,t =20 years , n= 4

100000=P(1+\frac{0.07}{4})^{(20\times 4)}

\Rightarrow P=\frac{100000}{(1+\frac{0.07}{4})^{80}}

\Rightarrow P=2496.11

∴P=$2496.11

6 0
3 years ago
If x/ 3=3/x then what is the value of x<br>1.-3<br>2.3<br>3.+-3​
Marizza181 [45]

Answer:

2.

Step-by-step explanation:

the answer is 3 if you solve it you will get it

6 0
3 years ago
Read 2 more answers
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