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Galina-37 [17]
3 years ago
7

Me puedes ayudar es para hoy porfavor ​

Mathematics
1 answer:
Inga [223]3 years ago
5 0

Answer:

mira a las base de las figuras y busca cual base matchs con la figuras de la figura prinsipal

Step-by-step explanation:

como el cono va con la del toda la izquierda de la de la mitad

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Mike and his dad are retiling his bathroom floor. They have budgeted $200 for the tiles and supplies. The tiles cost $1.85 each
Feliz [49]

Answer:

Equation: $114.90 + $1.85<em>x</em> = 200

Solution: They can buy 46 tiles.

Step-by-step explanation:

First, subtract 114.90 from both sides to get 1.85<em>x</em> = 85.10.

Divide 85.10 by 1.85 to get 46, which is the answer.

7 0
3 years ago
J+3/8 if j Equals 3/8
hodyreva [135]

Answer:

3

5

÷

j

=

3

8

Multiply the numerator of the first fraction by the denominator of the second fraction. Set this equal to the product of the denominator of the first fraction and the numerator of the second fraction.

(

3

5

)

⋅

8

=

j

⋅

3

Step-by-step explanation:Multiply the numerator of the first fraction by the denominator of the second fraction. Set this equal to the product of the denominator of the first fraction and the numerator of the second fraction.

(

3

5

)

⋅

8

=

j

⋅

3

6 0
3 years ago
Me need help in math:(help fast
Kamila [148]

Answer:

9.5 feet

Step-by-step explanation:

15.5-6=9.5

6 0
3 years ago
How many lines can be constructed perpendicular to AC that pass through point D?
Vladimir [108]

Answer:

1

Step-by-step explanation:

This is the answer by definition.

5 0
1 year ago
A closed, rectangular-faced box with a square base is to be constructed using only 36 m2 of material. What should the height h a
kkurt [141]

Answer:

b=h=\sqrt{6} m

Step-by-step explanation:

Let

Bas length of box=b

Height of box=h

Material used in constructing of box=36 square m

We have to find the height h and base length b of the box to maximize the volume of box.

Surface area of box=2b^2+4bh

2b^2+4bh=36

b^2+2bh=18

2bh=18-b^2

h=\frac{18-b^2}{2b}

Volume of box, V=b^2h

Substitute the values

V=b^2\times \frac{18-b^2}{2b}

V=\frac{1}{2}(18b-b^3)

Differentiate w. r.t b

\frac{dV}{db}=\frac{1}{2}(18-3b^2)

\frac{dV}{db}=0

\frac{1}{2}(18-3b^2)=0

\implies 18-3b^2=0

\implies 3b^2=18

b^2=6

b=\pm \sqrt{6}

b=\sqrt{6}

The negative value of b is not possible because length cannot be negative.

Again differentiate w.r.t b

\frac{d^2V}{db^2}=-3b

At  b=\sqrt{6}

\frac{d^2V}{db^2}=-3\sqrt{6}

Hence, the volume of box is maximum at b=\sqrt{6}.

h=\frac{18-(\sqrt{6})^2}{2\sqrt{6}}

h=\frac{18-6}{2\sqrt{6}}

h=\frac{12}{2\sqrt{6}}

h=\sqrt{6}

b=h=\sqrt{6} m

7 0
3 years ago
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