Answer:
F. 8
Step-by-step explanation:
The ratio of the long side to the short side is the same in similar triangles. The long side of triangle BAD is AD, which has length 20-4 = 16.
BD/DE = AD/BD
h/4 = 16/h
h^2 = 64 . . . . . . . multiply by 4h
h = 8 . . . . . . . . . . take the square root (matches selection F)
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<em>Comment on this geometry</em>
BD = √(AD·DC) is called the "geometric mean" of the segments AD and DC. This geometry has some other geometric mean relationships as well:
BC = √(AC·DC)
BA = √(AC·AD)
When you've got a squares bracket, this simply becomes the bracket twice, therefore, (r+s)2 becomes (r+s)(r+s)
You've then go to use FOIL, and this gives you r^2+rs+sr+s^2, and this cannot be simplified any further.
Therefore, the product of this is r^2 + s^2 + rs + sr
Hope this is what you're looking for :)
Answer:
B) 12
Step-by-step explanation:
C is the circumference, d is the diameter, and r is the radius. They are related by the following equations:
d = 2r
C = πd = 2πr
If d = 6.0, then r = 3.0.
If C / C' = 0.25, then:
(2πr) / (2πr') = 0.25
r / r' = 0.25
3 / r' = 0.25
r' = 12
The simplification of the given algebraic expression is;
yz = (z + 1)/z(z - 1)
<h3>How to simplify algebraic expressions?</h3>
We are given y left parenthesis z right parenthesis which is expressed as; yz
Now, we are given the algebraic expression that yz equals space fraction numerator z squared minus 1 over denominator z left parenthesis z minus 1 right parenthesis squared end fraction
z squared minus 1 over denominator z left parenthesis z minus 1 right parenthesis squared end fraction is expressed as; (z² - 1)/z(z - 1)²
Thus, our main expression is;
yz = (z² - 1)/z(z - 1)²
Factorizing the numerator and denominator gives;
yz = (z + 1)(z - 1)/z(z - 1)(z - 1)
(z - 1) is common to both numerator and denominator and as such, we now have;
yz = (z + 1)/z(z - 1)
Read more about Algebraic Expressions at; brainly.com/question/4344214
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