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3 years ago

Question Progress

Mathematics

1 answer:

Advocard [28]3 years ago

6 0

Answer:

C = 28.278 m

Step-by-step explanation:

The attached figure shows a circle whose diameter is 9 m.

Radius = Diameter/2

r = 9/2 = 4.5 m

The circumferance of the circle is given by :

C = 2πr

Put r = 4.5 m in the above formula

C = 2 × 3.142 × 4.5

= 28.278 m

So, the circumference of this circle is 28.278 m.

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Find the roots of each equation by factoring

Aleksandr [31]

Answer:

x=2

Step-by-step explanation:

Solution is attached

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3 years ago

Give an example of a quadratic with complex roots. Explain how you know it has complex roots.

Vladimir [108]

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4 years ago

Solve for x: 3/4x+5/8=4x

kompoz [17]

So, you have 3/4x + 5/8 = 4x. We can do this in two ways. Since fractions are harder to deal with, we can turn the fractions into whole numbers.

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3 years ago

joe is in debt $250, but he's saving $30 each month. using the equation, y=30x-250, how long will it take joe to have $230?

Vsevolod [243]

Answer:

Step-by-step explanation:

so in this equation we have 2 variables, and we must figure out what those variables mean:

y: "y" is the total amount of money joe has after subtracting his debt from it

x: "x" is the # of months as the cost of each month(30) is placed just before this variable

as y is the total amount of money joe has we need to substitute it for 230 to figure out how long it took for joe to recieve that much money

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480=30x

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4 years ago

Help me please ;-;!!!!! Use a coordinate grid to create a map of a town with at least five different locations, such as a house,

Sholpan [36]

A. Our diagram have six location: my house (2,1), a movie theater (5,3), the school (6,6), the police station (3,-2), the airport (-3,3), and the mall (-2,-3)

B. Distance between my house and the movie theater:
To calculate the distance we are going to use the points (2,1) and (5,3) to create a right triangle with tow legs of measures 3 and 2; the hypotenuse of the right triangle will be the distance between my house and the movie theater.
Using the Pythagorean theorem:
$d^2=3^2+2^2$
$d^2=9+4$
$d^2=13$
$d= \sqrt{13}$
We can conclude that the distance between my house and the movie theater is $\sqrt{13}$

Our second distance is the distance between the police station and the airport:
This time we are using the points (3,-2) and (-3,3) to create a right triangle with legs of measures 6 and 5; the hypotenuse of our triangle will be the the distance between our points:
$d^2=6^2+5^2$
$d^2=36+25$
$d^2=61$
$d= \sqrt{61}$
We can conclude that the distance between the police station and the airport is $\sqrt{61}$

C. Distance form the park to the Fire Station:
$d^2=3^2+1^2$
$d^2=9+1$
$d^2=10$
$d= \sqrt{10}$
We can conclude that the distance from the park to the Fire Station is $\sqrt{10}$

Distance from the stadium to the mall:
$d^2=2^2+1^2$
$d^2=4+1$
$d^2=5$
$d= \sqrt{5}$
We can conclude that the distance from the stadium to the mall is $\sqrt{5}$

D. What is the distance between your house and the mall?
Answer:
$d^2=4^2+4^2$
$d^2=16+16$
$d^2=32$
$d= \sqrt{32}$
$d=4 \sqrt{2}$
We can conclude that the distance between my house and the mall is $4 \sqrt{2}$

What is the distance between the movie theater and the school?
answer:
$d^2=3^2+1^2$
$d^2=9+1$
$d^2=10$
$d= \sqrt{10}$
We can conclude that the distance between the movie theater and the school is $\sqrt{10}$

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3 years ago