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ololo11 [35]
3 years ago
13

Please answer this question correctly I need it today please show work

Mathematics
1 answer:
oksano4ka [1.4K]3 years ago
7 0

Answer:

1: C(n) = 2.50 + 16n

2: $66.50

Step-by-step explanation:

Part 1

Each ticket costs $16 per person. If tickets for n persons were purchased, the total cost would be 16n.

There is also a one-time service fee of $2.50 that must be paid. Thus, for n tickets the total cost is

C(n) = 2.50 + 16n

Part 2

For n = 4, the expression evaluates to

C(4) = 2.50 + 16 (4) = $66.50

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what is remainder theorem ? explain how to use remainder thereom and factor theorem for linear polynomial .
elena55 [62]
Basically the Remainder theorem states  that the remainder of dividing a polynomial P(x) by (x - a) is given by P(a).

So for example if we divide  x^ 2 - 2x + 7  by x - 2  the remainder  will be 
2^2 - 2(2) + 7  =  7.. 

If the remainder is 0 then the divisor will be a factor of the polynomial.  This is the Factor Theorem and can be used to test if a given polynomial has a factor  x-a.
8 0
3 years ago
Find x. Assume that segments that appear tangent are tangent.
kipiarov [429]
Assuming that CB is tangent, this is just a right triangle with a hypotenuse of 20 and a side of 12 so by the Pythagorean Theorem:

20^2=12^2+x^2

400=144+x^2

x^2=400-144

x^2=256

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6 0
3 years ago
The side length of an equilateral triangle is 5 cm.<br><br> Find its perimeter
ollegr [7]
Answer: 15 cm

Step-by-Step Explanation:

Side Length (a) = 5cm
Perimeter = 3a

Therefore,
= 3a
= 3 * 5
= 15

Perimeter = 15 cm
8 0
2 years ago
Read 2 more answers
What is the area, in square centimeters, of the figure below? 2.4cm, 5.8cm
nirvana33 [79]

Answer:

13.92

Step-by-step explanation:

8 0
3 years ago
Find all solutions of each equation on the interval 0 ≤ x &lt; 2π.
Korvikt [17]

Answer:

x = 0 or x = \pi.

Step-by-step explanation:

How are tangents and secants related to sines and cosines?

\displaystyle \tan{x} = \frac{\sin{x}}{\cos{x}}.

\displaystyle \sec{x} = \frac{1}{\cos{x}}.

Sticking to either cosine or sine might help simplify the calculation. By the Pythagorean Theorem, \sin^{2}{x} = 1 - \cos^{2}{x}. Therefore, for the square of tangents,

\displaystyle \tan^{2}{x} = \frac{\sin^{2}{x}}{\cos^{2}{x}} = \frac{1 - \cos^{2}{x}}{\cos^{2}{x}}.

This equation will thus become:

\displaystyle \frac{1 - \cos^{2}{x}}{\cos^{2}{x}} \cdot \frac{1}{\cos^{2}{x}} + \frac{2}{\cos^{2}{x}} - \frac{1 - \cos^{2}{x}}{\cos^{2}{x}} = 2.

To simplify the calculations, replace all \cos^{2}{x} with another variable. For example, let u = \cos^{2}{x}. Keep in mind that 0 \le \cos^{2}{x} \le 1 \implies 0 \le u \le 1.

\displaystyle \frac{1 - u}{u^{2}} + \frac{2}{u} - \frac{1 - u}{u} = 2.

\displaystyle \frac{(1 - u) + u - u \cdot (1- u)}{u^{2}} = 2.

Solve this equation for u:

\displaystyle \frac{u^{2} + 1}{u^{2}} = 2.

u^{2} + 1 = 2 u^{2}.

u^{2} = 1.

Given that 0 \le u \le 1, u = 1 is the only possible solution.

\cos^{2}{x} = 1,

x = k \pi, where k\in \mathbb{Z} (i.e., k is an integer.)

Given that 0 \le x < 2\pi,

0 \le k.

k = 0 or k = 1. Accordingly,

x = 0 or x = \pi.

8 0
3 years ago
Read 2 more answers
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