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never [62]
3 years ago
13

Subtract 5 from 1/3 of 23

Mathematics
2 answers:
Alexxx [7]3 years ago
6 0
1/3 of 23 is:
23* (1/3)= 23/3

23/3 -5
= 23/3- 15/3
= 8/3
= 2 2/3

The final answer is 2 2/3~
Kitty [74]3 years ago
4 0
Answer= 2.6

Method= 1/3 of (of = x on calculator) 23= 7.6
7.6-5= 2.6
:)
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Eduardo and Paul are leaving the same airport in Florida. Eduardo’s flight to Jamaica is 273 miles long. Paul's flight to Hondur
k0ka [10]

Answer:

B. 41.8° is the correct answer

Step-by-step explanation:

We are given that,

Length of Eduardo's flight path = 273 miles

Length of Paul's flight path = 357 miles

Distance between their destinations = 238 miles.

Now, using the law of cosines, we get,

238^2=273^2+357^2-2\times 273\times 357\times \cos \theta

i.e. 56644=74529+127449-194922\times \cos \theta

i.e. 56644=201978-194922\times \cos \theta

i.e. 194922\times \cos \theta=145334

i.e. \cos \theta=0.7456

i.e. \theta=\arccos 0.7456

i.e.  θ = 41.8°

Hence, the angle between their flight paths is 41.8°.

4 0
3 years ago
Write an equation to represent the following description. The difference of seven times a number and 15 is 41.
chubhunter [2.5K]

Answer: 3

7x + 15 = 41 or 7x - 15 = 41

7 0
3 years ago
Read 2 more answers
Which of the following is not a way to represent the solution of the inequality 2(x − 1) greater than or equal to −12?
maxonik [38]
First you need to simplify the left side of the equation to get 2x-2 \geq -12
Then you add by two on both sides to get 2x \geq -10
Finally you divide by 2 on both sides to get x \geq -5
6 0
3 years ago
If Luke's brother earns $15 per hour, he will get a 6% increase per hour. How
jeka94
Luke’s brother will now make $15.90 per hour.
5 0
2 years ago
two mechanics worked on a car. The first mechanic worked for 10 hrs, and the second mechanic worked for 5 hours. Together they c
soldier1979 [14.2K]

Answer:

The first mechanic $90/hour and the second charged $70/hour

Step-by-step explanation:

Lets start off by letting x be the first mechanics rate and y being the second mechanics rate. We know that the first mechanic worked 5 hours and that the second mechanic worked 10 hours and together they charged 1150. An equation to express this would be:

5x+10y = 1150

We also know that together they charged 160/per hour. An equation to express this would be:

x+y = 160

Now we can solve the second equation for x or the first mechanics rate.

x+y = 160

x = 160 - y

Now that we have an expression for x we can plug that back into the first equation and solve for y or how much the second mechanic charged.

5x+10y=1150 plug in x =160-y

5(160-y)+10y=1150 Distribute

800 -5y+10y = 1150 Combine like terms

800 +5y = 1150 Subtract 800 from both sides

5y = 350 divide by 5

y = 70

So we know that the second mechanic charged $70/hour. We also know that(from our work before) that the first mechanic charges $160 - the rate the second mechanic charged. We know that's $70/hour so we can plug in and solve for the first rate.

x = 160-y

x = 160-70

x = 90

So we know that the first mechanic charged $90/hour and the second mechanic charged $70/hour.

5 0
3 years ago
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