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pickupchik [31]
3 years ago
6

PLA HELP ME 100 POINTS FOR TO ANSWER

Mathematics
2 answers:
Kryger [21]3 years ago
8 0

Answer: A

Step-by-step explanation: e2020

Marina86 [1]3 years ago
7 0

Answer:

it is B

Step-by-step explanation:

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Becky and Don live 210 miles apart and plan to visit each other for a week. They decide to leave at the same time, drive toward
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If they don't stop 1 hour and a half.

90 miles away from Becky and 120 away from Don

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What is the value of the expression?
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I need help with #15
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F (x) = 3x - 5, find f (7)
evablogger [386]

Answer:

f(7) = 16

Step-by-step explanation:

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2 years ago
Determine the common ratio and find the next three terms of the geometric sequence 9,3sqrt3,3
Maru [420]

Answer:

Fourth term: a_4 = 9 * (\frac{\sqrt{3}}{3})^{(4 - 1)} = 9 * (\frac{\sqrt{3}}{3})^{3} = \sqrt{3}

Fifth term: a_5 = 9 * (\frac{\sqrt{3}}{3})^{(5 - 1)} = 9 * (\frac{\sqrt{3}}{3})^{4} = 1

Sixth term: a_6 = 9 * (\frac{\sqrt{3}}{3})^{(6 - 1)} = 9 * (\frac{\sqrt{3}}{3})^{5} =\frac{\sqrt{3}}{3}

Step-by-step explanation:

The geometric progression is:

9, 3 \sqrt{3}, 3...

The first term, a, is 9

To find the common ratio, r, all we have to do is divide a term by its preceding term.

Let us divide the second term by the first:

r = \frac{3\sqrt{3}}{9}\\ \\r = \frac{\sqrt{3}}{3}

That is the common ratio.

Geometric progression is given generally as:

a_n = ar^{(n - 1)}

where a = first term

r = common ratio

a_n = nth term

We need to find the 4th, 5th and 6th terms.

Fourth term: a_4 = 9 * (\frac{\sqrt{3}}{3})^{(4 - 1)} = 9 * (\frac{\sqrt{3}}{3})^{3} = \sqrt{3}

Fifth term: a_5 = 9 * (\frac{\sqrt{3}}{3})^{(5 - 1)} = 9 * (\frac{\sqrt{3}}{3})^{4} = 1

Sixth term: a_6 = 9 * (\frac{\sqrt{3}}{3})^{(6 - 1)} = 9 * (\frac{\sqrt{3}}{3})^{5} =\frac{\sqrt{3}}{3}

5 0
3 years ago
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