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3 years ago

What is the median of the set 5,6,9,11,12,14,20,23,24,24,30?

Mathematics

1 answer:

Anon25 [30]3 years ago

7 0

Answer:

The median is the one in the middle

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WHAT NUMBER IS MISSING IN THE FOLLOWING SERIES: 4 --‐ 5 --‐ 7 --‐ 10 --‐ 14 --‐ 19 --‐ ___

Kruka [31]

Answer:

simple, when you add another number into the sequence, it is increased by 1 per each number...

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3 years ago

Without calculating would 0.4+(2+0.6)be less than, greater than,or equal to 3? Explain

masya89 [10]

The answer would be “Greater than.”

3 0

3 years ago

Urgent - Please help me with these questions!

Schach [20]

Answer:

1 thousand i think hope this helps!

Step-by-step explanation:

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2 years ago

How do I solve 8x+3(x+5)-5(x-4)

adell [148]

Answer:

6x + 35

Step-by-step explanation:

First Distribute

8x + 3x + 15 -5x +20

Then collect like terms

6x + 35

to solve you would need the value of x to plug it!

7 0

3 years ago

What is the nth term?

kumpel [21]

Let $a_k$ denote the kth term of the sequence. Then

$a_k=a_1+d(k-1)$

where d is the common difference between consecutive terms in the sequence and a₁ is the first term.

The sum of the first n terms is

$S_n=\displaystyle\sum_{k=1}^na_k=a_1+a_2+\cdots+a_{n-1}+a_n$

From the formula for $a_k$ , we get

$S_n=\displaystyle\sum_{k=1}^n(a_1+d(k-1))=a_1\sum_{k=1}^n1+d\sum_{k=1}^n(k-1)$

$S_n=\displaystyle na_1+d\sum_{k=0}^{n-1}k$

$S_n=na_1+\dfrac{d(n-1)n}2$

$S_n=\dfrac n2(2a_1-d+dn)$

So we have $d=-5$ , and $2a_1-d=16$ so that $a_1=\frac{11}2$ .

Then the nth term in the sequence is

$a_n=\dfrac{11}2-5(n-1)=\boxed{\dfrac{21-10n}2}$

7 0

3 years ago