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2 years ago

14

What is the median of the set 5,6,9,11,12,14,20,23,24,24,30?

1 answer:

Anon25 [30]2 years ago

7 0

Answer:

14

The median is the one in the middle

;p

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Which 2 equations would you use to solve this system?

slega [8]

Answer:

x-y=4

and

x+y=32 is <u>your</u><u> </u><u>equation</u>

<u>d</u><u>i</u><u>f</u><u>f</u><u>e</u><u>r</u><u>e</u><u>n</u><u>c</u><u>e</u><u> </u><u>o</u><u>f</u><u> </u><u>t</u><u>w</u><u>o</u><u> </u><u>n</u><u>u</u><u>m</u><u>b</u><u>e</u><u>r</u><u> </u><u>=</u><u>x-y</u><u> </u><u>is</u><u> </u><u>equal</u><u> </u><u>to</u><u> </u><u>4</u>

<u>s</u><u>u</u><u>m</u><u> </u><u>o</u><u>f</u><u> </u><u>t</u><u>w</u><u>o</u><u> </u><u>n</u><u>u</u><u>m</u><u>b</u><u>e</u><u>r</u><u>=</u><u>x</u><u>+</u><u>y</u><u> </u><u>i</u><u>s</u><u> </u><u>e</u><u>q</u><u>u</u><u>a</u><u>l</u><u> </u><u>t</u><u>o</u><u> </u><u>3</u><u>2</u>

<u>x</u><u>-</u><u>y</u><u>=</u><u>4</u><u>.</u><u>.</u><u>.</u><u>.</u><u>.</u><u>.</u><u>.</u><u>(</u><u>1</u><u>)</u>

<u>x</u><u>+</u><u>y</u><u>=</u><u>3</u><u>2</u><u>.</u><u>.</u><u>.</u><u>.</u><u>.</u><u>.</u><u>.</u><u>(</u><u>2</u><u>)</u>

<u>a</u><u>d</u><u>d</u><u>i</u><u>n</u><u>g</u><u> </u><u>equation</u><u> </u><u>1</u><u> </u><u>a</u><u>n</u><u>d</u><u> </u><u>2</u>

<u>x</u><u>-</u><u>y</u><u> </u><u>+</u><u>x</u><u>+</u><u>y</u><u>=</u><u>4</u><u>+</u><u>3</u><u>2</u>

<u>2</u><u>x</u><u>=</u><u>3</u><u>6</u>

<u>x</u><u>=</u><u>3</u><u>6</u><u>/</u><u>2</u><u>=</u><u>1</u><u>6</u><u>a</u><u>n</u><u>s</u><u>w</u><u>e</u><u>r</u>

<u>s</u><u>u</u><u>b</u><u>s</u><u>t</u><u>i</u><u>t</u><u>u</u><u>t</u><u>i</u><u>n</u><u>g</u><u> </u><u>value</u><u> </u><u>of</u><u> </u><u>y</u><u> </u><u>in</u><u> </u><u>equation</u><u> </u><u>1</u>

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<u>1</u><u>6</u><u>-</u><u>4</u><u>=</u><u>y</u>

<u>y</u><u>=</u><u>1</u><u>2</u><u> </u><u>a</u><u>n</u><u>s</u><u>w</u><u>e</u><u>r</u>

4 0

2 years ago

ollegr [7]

Answer:

$FC=25.9$

Step-by-step explanation:

<u>Congruent Triangles</u>

The figure shows two triangles FCD and FED. One of their sides is the radius of the circle, they both form a 90° angle with the line CD and ED and they share the same segment FD.

Thus, both triangles are congruent and we have the length of a side (12 units), one common side (the hypotenuse) and one unknown leg that must be equal. Therefore

$13x-16=4x+11$

Solving

$9x=27$

$x=3$

The required side FD is the hypotenuse of any of the triangles. The unknown leg can be calculated by

$13x-16=23$

Or

$4x+11=23$

Thus

$FD^2=12^2+23^2=673$

Solving

$FD=\sqrt{673}$

$\boxed{FC=25.9}$

5 0

2 years ago

A rectangular deck is 12ft by 14ft. When the length and width are increased by the same amount, the area becomes 288sq. ft. By h

Cerrena [4.2K]

Dimensions of rectangle = 12 + x and 14 + x

(12 + x) (14 + x) = 288

x^2 + 26x + 168 = 288

x^2 + 26x - 120 = 0

(x + 30) (x - 4) = 0

x=-30, x =4

since 4 is positive

the dimensions increased by 4 feet

check the answer

12+4 = 16

14 +4 = 18

18*16 =288

3 0

3 years ago

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What are the dimensions (length and width) if the poster is enlarged by a factor of 1.5 ? (Remember multiply the factor by the d

Veseljchak [2.6K]

Use socratic or photomath

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3 years ago

6=2(y+2) i need help

Snowcat [4.5K]

Answer:

y=1

Step-by-step explanation:

6=2(y+2)

6=2y+4

2=2y

y=1

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2 years ago

Read 2 more answers