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2 years ago

Find the value of x.asnswers 50/3756

Mathematics

1 answer:

vovikov84 [41]2 years ago

6 0

Answer:

x = 6

Step-by-step explanation:

PR / RQ = P'R' / R'Q'

x / 9 = 10 / 15

cross-multiply:

15x = 90

x = 90/15

x = 6

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One evening in snowed in several towns the number of inches of snow received are shown in the list below

Yuri [45]

Answer:

Please find the required line chart created with MS Excel

Step-by-step explanation:

Question:

The given data are;

3/4, 1 1/2, 2, 1 1/4, 3/4, 2, 1 1/2, 1 1/4, 1 1/2, 1/2, 1

In the question, it is required to create a line plot to represent the data

The given data can be sorted in ascending order in decimal form as follows;

0.5, 0.75, 0.75, 1, 1.25, 1.25, 1.5, 1.5, 1.5, 2

The line chart created with MS Excel is attached.

4 0

3 years ago

20% of US High School teens vape. A local High School has implemented campaigns to reduce vaping among students and believes tha

zaharov [31]

Answer:

10.93% probability of observing 51 or fewer vapers in a random sample of 300

Step-by-step explanation:

I am going to use the normal approximation to the binomial to solve this question.

Binomial probability distribution

Probability of exactly x sucesses on n repeated trials, with p probability.

Can be approximated to a normal distribution, using the expected value and the standard deviation.

The expected value of the binomial distribution is:

$E(X) = np$

The standard deviation of the binomial distribution is:

$\sqrt{V(X)} = \sqrt{np(1-p)}$

Normal probability distribution

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

When we are approximating a binomial distribution to a normal one, we have that $\mu = E(X)$ , $\sigma = \sqrt{V(X)}$ .

In this problem, we have that:

$n = 300, p = 0.2$

$\mu = E(X) = np = 300*0.2 = 60$

$\sigma = \sqrt{V(X)} = \sqrt{np(1-p)} = \sqrt{300*0.2*0.8} = 6.9282$

What is the approximate probability of observing 51 or fewer vapers in a random sample of 300?

Using continuity corrections, this is $P(X \leq 51 + 0.5) = P(X \leq 51.5)$ , which is the pvalue of Z when X = 51.5 So

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{51.5 - 60}{6.9282}$

$Z = -1.23$

$Z = -1.23$ has a pvalue of 0.1093.

10.93% probability of observing 51 or fewer vapers in a random sample of 300

4 0

2 years ago

Find the probability that the hitter makes 10 outs in 10 consecutive at-bats, assuming at-bats are independent events. Hint:

emmainna [20.7K]

Answer:

0.037

Step-by-step explanation:

If the hitter makes an out 72% of the time, then the probabilty that he makes hit in 1 at-bat is $p=0.72$ and the probabilty that he doesn't make hit in 1 at-bat is $q=1-p=1-0.72=0.28.$