Answer:
Step-by-step explanation:
We know that the standard quadratic equation is ax^2+bx+c=0
Let's compare all the given equation to it and , find discriminant.
1. a=2, b= -7, c=-9
So it has 2 real number solutions.
2. a=1, b=-4, c=4
So it has only 1 real number solution.
3. a=4, b=-3, c=-1
So it has 2 real number solutions.
4. a=1, b=-2, c=-8
So it has 2 real number solutions.
5. a=3, b=5, c=3
Thus it does not has real solutions.
Greetings!
Answer:
2y = x - 6
Step-by-step explanation:
First, we must find the slope of the current equation.
This is the number in front of the x.
Seeing as this is -2x, the slope of this line is -2
When finding the slope of a line perpendicular, you need to find the
So, in this case it is:
The negatives cancel out which leave
So the gradient is
Now, to find the equation of a line, you need to use:
y - y1 = m(x - x1)
Where ya and x1 are the values in the coordinates (2 , -2)
So y1 = -2, x1 = 2, and m is a half. Plug these values in:
y - - 2 =
We need to get rid of the half so we multiply the whole equation by 2:
2y - - 4 = (x - 2)
The minus and the negative turn into a positive:
2y + 4 = x - 2
And now simply move the +4 over to the other side, making it a negative:
2y = -2 - 4 + x
Simplify:
2y = x - 6
<h3>So the equation of the line is 2y = x - 6</h3>