Question

In the figure below, what is the value of xº?

Answer 1

Answer:

x = 32

Step-by-step explanation:

The exterior angle of a triangle is equal to the sum of the opposite interior angles

100 = 68+x

Subtract 68 from each side

100 -68 = x

32 =x

Answer 2

$\huge\bold{Given :}$

Angle AOB = 100°

Angle OBC = 68°

Angle BCO = $x°$

$\huge\bold{To\:find :}$

The value of $x°$.

$\large\mathfrak{{\pmb{\underline{\orange{Solution}}{\orange{:}}}}}$

$\implies {\blue {\boxed {\boxed {\purple {\sf {C.\:x°\:=\:32°}}}}}}$

$\large\mathfrak{{\pmb{\underline{\red{Step-by-step\:explanation}}{\red{:}}}}}$

An exterior angle of a triangle is equal to sum of two opposite interior angles.

And so we have,

➪ ∠ AOB = ∠ OBC + ∠ BCO

➪ 100° = 68° + $x°$

➪ $x°$ = 100° - 68°

➪ $x°$ = 32°

Therefore, the value of $x°$ is 32°.

$\large\mathfrak{{\pmb{\underline{\blue{To\:verify}}{\blue{:}}}}}$

∠ AOB = ∠ OBC + ∠ BCO

✒ 100° = 68° + 32°

✒ 180° = 100°

✒ L. H. S. = R. H. S.

$\boxed{Hence\:verified.}$

(Note: Kindly refer to the attached file.)

$\huge{\textbf{\textsf{{\orange{My}}{\blue{st}}{\pink{iq}}{\purple{ue}}{\red{35}}{\green{ヅ}}}}}$