Answer:
89.804
Step-by-step explanation:
First isolate the "y" in the equation.
2y - x = -12 Add x on both sides
2y - x + x = -12 + x
2y = -12 + x Divide 2 on both sides to get "y" by itself


Your slope is
.
For the equation of the line to be parallel to the given equation, the slopes have to be the same. So the parallel line's slope is also 
y = mx + b

To find "b", you plug in the point (18,2) into the equation


2 = 9 + b Subtract 9 on both sides
2 - 9 = 9 - 9 + b
-7 = b
Your equation is:

a)
FH = 102, FG = 5x + 9. HG = 9x - 5 <em>Given</em>
FG + HG = FH <em>Segment addition postulate</em>
5x + 9 + 9x - 5 = 102 <em>Substitution</em>
14x + 4 = 102 <em>Simplify (added like terms)</em>
14x = 98 <em>Subtraction property of equality</em>
x = 7 <em>Division property of equality</em>
b) FG = 5x + 9 = 5(7) + 9 = 35 + 9 = 44
c) HG = 9x - 5 = 9(7) - 5 = 63 - 5 = 58
Answers: a = 7, b = 44, c = 58
Answer:12 in
Step-by-step explanation:
Answer:
g(x)= 5
Step-by-step explanation:
Evaluate F(X) for 2
3(2)-1
6-1
5
And that is the value of G(X)