Evaluated and Yes it would be 0
The product of two even numbers is even.
Let m and n be any integers so that 2m and 2k are two even numbers.
The product is 2m(2k) = 2(2mk), which is even.
Things to think about:
Why didn’t I just show you by using any two even numbers like the number 4 and the number 26?
Why did I change from "m" to "k" ? Are they really different numbers or could they be the same?
Why did I specifically say that m and k were integers?
The product of two odd numbers is an odd number.
Let m and k be any integers. This means that 2m+1 and 2k+1 are odd numbers.
The product is 4mk + 2m + 2k + 1 (hint: I used FOIL) which can be written as
2 ( 2mk + m + k ) + 1 which is an odd number.
Given, IJ = 3x + 3, HI = 3x - 1, and HJ = 3x + 8.
Since I is a point on line segment HJ, we can write
Put x=2 in HJ=3x+8.
Therefore, the numerical length of HJ is 14.
Answer:
240
Step-by-step explanation:
So here’s the step by step (for the show your work thingy)
so we can write an equation
0.05x=12
We use 0.05 becuase 5 percent is basically 5/100 and the x is used becuase we don’t know what the number is and the =12 is for the number that came out as a final result
ow we can solve the equation
x=12/0/05
x=240
Final answer is 240
Answer:
Your answer is A.
Step-by-step explanation:
Looking at the graphing two-equation: y = x^3 -3 and y = x^2+6 are up there, it can help us determine the limit of domain.
The dot is the x<=2 for equation y=x^3-3.
The circle is x>2 for equation y=x^2+6
