Answer:
Step-by-step explanation:
GIVEN: A hotel charges a 
annual fee plus an additional 
for each night you stay there.
TO FIND: average cost per night if you stay at the hotel for 
nights.
SOLUTION:
Annual fee charged by hotel 
amount charged each night we stay there 
Total number of nights we stay 
Total amount paid for nights
Total amount paid 
average cost per night 
putting values,
average cost per night 
Hence average cost per night if we stay at hotel for days is
Probability that the first 2 of the friends to show up to the movie are friends he has known since kindergarten but the third not is 1/10
Total friends = 10
Friends from kindergarten = 4
Probability is the chance that a given event will occur. Probability of an event lies within 0 to 1
P(E) = Favourable outcomes / Total outcomes
Probability of getting 1st friend from kindergarten = 4/10
Probability of getting 2nd friend from kindergarten = 3/9
Probability of getting 3rd friend not from kindergarten = 6/8
Since all these probabilities are independent, We can use Multiplicative identity. Thus,
Required probability is 4/10 * 3/9 * 6/8
= 1/10
Thus, Probability that the first 2 of the friends to show up to the movie are friends he has known since kindergarten but the third not is 1/10
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It is D you have subtract them
Answer:
No
Step-by-step explanation:
No because the measure of two sides are always greater than the third side
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