A linear sequence (i.e. where the 1st difference is always the same) has 5th term 6 and 92nd term 354. What is the 57th term?
2 answers:
Answer:
a₅₇ = 214
Step-by-step explanation:
The n th term of an arithmetic sequence is
= a₁ + (n - 1)d
where a₁ is the first term and d the common difference
Given a₅ = 6 and a₉₂ = 354 , then
a₁ + 4d = 6 → (1)
a₁ + 91d = 354 → (2)
Subtract (1) from (2) term by term to eliminate a₁
0 + 87d = 348
87d = 348 ( divide both sides by 87 )
d = 4
Substitute d = 4 in (1) and solve for a₁
a₁ + 4(4) = 6
a₁ + 16 = 6 ( subtract 16 from both sides )
a₁ = - 10
Then
a₅₇ = - 10 + (56 × 4 ) = - 10 + 224 = 214
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<em>The result is -13</em>
<h2>Explanation:</h2><h2 />Here we have the following addition problem:
So let's solve this step by step:
Step 1. Perform two plus two.
So:
Step 2. Perform the subtraction.
Since the sign (-) accompanies 17 which is greater than 4, then we perform the subtraction and add the sign (-) to the result. So:
<em>Finally, the result is -13</em>
<h2>Learn more:</h2>Distributive property: brainly.com/question/10794694
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