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Oxana [17]
3 years ago
7

What is the logical conclusion, based upon the information given in the

Mathematics
1 answer:
Stolb23 [73]3 years ago
4 0
Clearly says Bleeker is before Astor Place.
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When using re-grouping to solve 21 x 43, what are the four products that would be calculated and then added?
pshichka [43]

Answer:

c

Step-by-step explanation:

21×43

=(20+1)×(40+3)

=800+40+60+3

3 0
3 years ago
Read 2 more answers
The length and width of a rectangle are in a 7:2 ratio. Find the width of the perimeter is 72.
scoray [572]
<span>length = 7x
</span><span>width = 2x

2(7x + 2x) = 72
7x + 2x = 72/2
9x = 36
x = 36/9
x = 4
</span>
width = 2x = 2 * 4 = 8 units<span>


</span>
7 0
3 years ago
Can someone demonstrate the process for solving y= 1/2x +4
mash [69]
Basically 1/2 equals 2 and times x equals 2x. X is a variable an unknown number so 2x +4 and that's how you get your answer
5 0
3 years ago
The low temperature was 35 f. This was 13 f lower than the daytime high temperature. Write an equaton to determin wheter the hig
alina1380 [7]
If x is the high temperature, you can write the following equation:
x = 35°F + 13°F

Which simplifies to:
x = 48°F
3 0
3 years ago
I have the first part but I don't know how to do the second part<br><br> h e l p
Debora [2.8K]

\bf \begin{array}{cll} \stackrel{ordinal}{position}&\stackrel{term}{value}\\ \cline{1-2} 1&12\\ 2&12+d\\ 3&12+d+d\\ 4&12+d+d+d\\ &12+3d \end{array}\qquad \implies ~\hfill \begin{array}{llll} \stackrel{\textit{4th term}}{12+3d}~~=~~\stackrel{\textit{4th value}}{3}\\\\ 3d=-9\implies d = \cfrac{-9}{3}\\\\ \stackrel{\textit{common difference}}{d = -3} \end{array}

well, we know the common difference is -3, to go from the 4th term to the 8th term, we need to add "d" 4 times or namely 3+4(-3), likewise to go from the 13th term to the 19th term we have to add "d" 6 times, or namely -24 + 6(-3).

\bf \stackrel{\textit{8th term}}{3+4(-3)}\implies 3-12\implies -9 \\\\\\ \stackrel{\textit{19th term}}{-24 + 6(-3)}\implies -24-18\implies -42

3 0
3 years ago
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