Answer:
B. 970,000
Step-by-step explanation:
<u>M</u><u>o</u><u>v</u><u>e</u><u> </u><u>t</u><u>h</u><u>e</u><u> </u><u>d</u><u>e</u><u>c</u><u>i</u><u>m</u><u>a</u><u>l</u><u> </u><u>5</u><u> </u><u>p</u><u>l</u><u>a</u><u>c</u><u>e</u><u>s</u><u> </u><u>t</u><u>o</u><u> </u><u>t</u><u>h</u><u>e</u><u> </u><u>r</u><u>i</u><u>g</u><u>h</u><u>t</u><u>,</u><u> </u><u>s</u><u>i</u><u>n</u><u>c</u><u>e</u><u> </u><u>t</u><u>h</u><u>e</u><u> </u><u>e</u><u>x</u><u>p</u><u>o</u><u>n</u><u>e</u><u>n</u><u>t</u><u> </u><u>i</u><u>s</u><u> </u><u>a</u><u> </u><u>p</u><u>o</u><u>s</u><u>i</u><u>t</u><u>i</u><u>v</u><u>e</u><u> </u><u>5</u><u>.</u>
9.7 x 10⁵ = 970,000.
<u>I</u><u>f</u><u> </u><u>i</u><u>t</u><u> </u><u>i</u><u>s</u><u> </u><u>a</u><u> </u><u>n</u><u>e</u><u>g</u><u>a</u><u>t</u><u>i</u><u>v</u><u>e</u><u> </u><u>e</u><u>x</u><u>p</u><u>o</u><u>n</u><u>e</u><u>n</u><u>t</u><u>,</u><u> </u><u>y</u><u>o</u><u>u</u><u> </u><u>w</u><u>o</u><u>u</u><u>l</u><u>d</u><u> </u><u>h</u><u>a</u><u>v</u><u>e</u><u> </u><u>t</u><u>o</u><u> </u><u>m</u><u>o</u><u>v</u><u>e</u><u> </u><u>t</u><u>h</u><u>e</u><u> </u><u>d</u><u>e</u><u>c</u><u>i</u><u>m</u><u>a</u><u>l</u><u> </u><u>t</u><u>o</u><u> </u><u>t</u><u>h</u><u>e</u><u> </u><u>l</u><u>e</u><u>f</u><u>t</u><u>.</u>
Answer:
77
Step-by-step explanation:
The area of a rectangle is A = lw. 'A', the area, is 3927, and 'w', the width, is 51. By substituting the values in, we get that 3927 = 51L. Dividing both sides by 51, we get that L, the length, is 77.
R≈1.02
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Given: F = {(0, 1), (2, 4), (4, 6), (6, 8)} and G = {(2, 5), (4, 7), (5, 8), (6, 9), (7, 5)}
Snezhnost [94]
9514 1404 393
Answer:
9
Step-by-step explanation:
The ordered pair (2, 4) in the relation for function F tells you F(2) = 4.
The ordered pair (2, 5) in the relation for function G tells you G(2) = 5.
Then the sum is ...
(F+G)(2) = F(2) +G(2) = 4 +5
(F+G)(2) = 9
Answer:
A= 5/7b +8
Step-by-step explanation:
The basic idea is that you can do anything you want (except divide by
zero) to either side of the equation, so long as you do the same thing
to the other side, too.