Answer:
m(∠C) = 18°
Step-by-step explanation:
From the picture attached,
m(arc BD) = 20°
m(arc DE) = 104°
Measure of the angle between secant and the tangent drawn from a point outside the circle is half the difference of the measures of intercepted arcs.
m(∠C) = ![\frac{1}{2}[\text{arc(EA)}-\text{arc(BD)}]](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B2%7D%5B%5Ctext%7Barc%28EA%29%7D-%5Ctext%7Barc%28BD%29%7D%5D)
Since, AB is a diameter,
m(arc BD) + m(arc DE) + m(arc EA) = 180°
20° + 104° + m(arc EA) = 180°
124° + m(arc EA) = 180°
m(arc EA) = 56°
Therefore, m(∠C) = 
m(∠C) = 18°
Answer:
4/3
Step-by-step explanation:
you use slope formula
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<em>Look</em><em> </em><em>at</em><em> </em><em>the</em><em> </em><em>attached</em><em> </em><em>picture</em>
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<em>Good</em><em> </em><em>luck</em><em> </em><em>on</em><em> </em><em>your</em><em> </em><em>assignment</em>
we conclude that if the scale factor from S to M is 3/2, then the scale factor from M to S is 2/4.
<h3>
</h3><h3>What is the scale factor from M to S?</h3>
Suppose we have a figure S. If we apply a stretch of scale factor K to our figure S, we can say that all the dimensions of figure S are multiplied by K.
So, if S represents the length of a bar, then after the stretch we will get a bar of length M, such that:
M = S*K
If that scale factor is 3/2, then we have the case of the problem:
M = (3/2)*S
We can isolate S in the above relation:
(2/3)*M = S
Now we have an equation (similar to the first one) that says that the scale factor from M to S is 2/3.
Then we conclude that if the scale factor from S to M is 3/2, then the scale factor from M to S is 2/4.
If you want to learn more about scale factors:
brainly.com/question/25722260
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