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Cerrena [4.2K]
2 years ago
7

Match each function with its function. Use function composition to determine your answer

Mathematics
1 answer:
Ket [755]2 years ago
8 0

Answer:

C

Step-by-step explanation:

idk

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For which value of x is the row in the table of values incorrect
Westkost [7]

Answer:

x = 2 is incorrect

Step-by-step explanation:

The answer should be 3 instead of 4

7 0
3 years ago
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Which ordered pair is a solution to the equation y=4-6x?
Alex777 [14]

Answer:

the answer to this is b( 2,-8)

7 0
3 years ago
What is the square root of -1​
Romashka [77]

Answer:

i

Step-by-step explanation:

Now, before you think I'm just stealing points, let me explain. The square root of a number is the number that, if you multiply it by itself, it equals that number. The square root of 4 is 2, because 2 * 2 = 4.

Also, a negative number times another negative number, is a positive number. -2 * -2 = 4

With both of those true, then what number could be multiplied by itself to equal a negative number? i.

i is a weird number that I don't really know how to explain all that well. I am sorry, but that is all that I can give you. i is very complex and has various different equivalents, and different meanings, but i is equal to \sqrt{-1}.

Hope that this helps!

3 0
3 years ago
A) A square has an area of 64 cm?
kolbaska11 [484]

Answer:

perimeter of square =34cm

Step-by-step explanation:

its 64..area

normally we find area by calculating side ×side

so 8×8

=64

  • so its 34cm....
7 0
2 years ago
Solve by completing the square
Sveta_85 [38]

\qquad\qquad\huge\underline{{\sf Answer}}☂

Let's solve ~

\qquad \sf  \dashrightarrow \:  {x}^{2} + 8x = 33

\qquad \sf  \dashrightarrow \:  {x}^{2} + 8x +16 = 33 + 16

\qquad \sf  \dashrightarrow \: (x + 4) {}^{2}  = 49

\qquad \sf  \dashrightarrow \: x + 4 =  \sqrt{49}

\qquad \sf  \dashrightarrow \: x + 4 =  \pm7

Hence, there are two solutions ~

  • 1. when x + 4 = 7

\qquad \sf  \dashrightarrow \: x + 4 = 7

\qquad \sf  \dashrightarrow \: x = 7 - 4

\qquad \sf  \dashrightarrow \: x = 3

  • 2. when x + 4 = -7

\qquad \sf  \dashrightarrow \: x + 4 =  - 7

\qquad \sf  \dashrightarrow \: x  =  - 7 - 4

\qquad \sf  \dashrightarrow \: x  =   - 11

I hope you understood ~

8 0
2 years ago
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