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Anastasy [175]
2 years ago
15

For any positive integer n, prove that n^3-n is divisible by 6.please answer ​

Mathematics
1 answer:
ikadub [295]2 years ago
3 0

Answer:

yes it is true

Step-by-step explanation:

if we take n=2 then

2°3-2=8-2=6

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Pablo simplified the expression (2 Superscript negative 4 Baseline) Superscript negative 2 as shown.
Lady_Fox [76]

Answer:

<h3>He should have found 8 as the exponent, not –8.</h3>

Step-by-step explanation:

Given the expression simplified by Pablo as (2^{-4})^{-2}

On simplification we have;

According to one of the law of indices (a^{m})^{n} = a^{mn}

Applying this law to the question will give;

(2^{-4})^{-2}\\=2^{-4*-2}  \\\= 2^{8}

Based on the calculation above, the exponent of 2 is 8 which means that Pablo should have found 8 as the exponent, not –8.

7 0
3 years ago
Solve for x. X-8 = -20 12 -28 28 2-12​
Semmy [17]

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Step-by-step explanation:

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2 years ago
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The mean is the average you're used to, where you add up all the numbers and then divide by the number of numbers. The median is the middle value in the list of numbers. Mode is the number which appears most often in a set of numbers.

Hope this helps you :)

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