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3 years ago

A student took out a simple interest loan for 2400 for 2 years at a rate of 7%. What is the interest on the loan?

Mathematics

1 answer:

Stels [109]3 years ago

5 0

Answer:

using the 7% interest rate the interest rate is 168 due to the fact if you take 2400 x .07 you get 168 however I don't know if it asks that but in order to see exactly how much money would be in there you would have to add the 168 to the 2400 if you are to add that to the 2400 that was originally put in the bank you would come up to 2568

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Show your work please no links please!:)

BabaBlast [244]

Answer:

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Step-by-step explanation:

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3 years ago

The service time distribution describes the probability P that the service time of the customer will be no more than T hours. If

Molodets [167]

Answer: option d.

Step-by-step explanation:

You have the following formul given in the problem:

$p=1-e^{-mt}$

You know that:

The number of customers serviced in an hour by the technical support representative is 6 costumbers, therefore:

$m=6$

As the problem asked for the probability that a costumber will be on hold less than 30 minutes, we know that:

$t=0.5$

Substitute the values above into the formula.

Then, you obtain:

$p=1-e^{-(6)(0.5)}=0.95$ or 95%

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3 years ago

A triangle has side lengths of 33,56, and 65. Is it a right triangle? Explain.

soldier1979 [14.2K]

U can see if it is a right triangle bu using the pythagorean theorem (or however it is spelled)

a^2 + b^2 = c^2....where a and b are the legs and c is the hypotenuse (the largest side)

so lets sub our numbers in and see if they equal
33^2 + 56^2 = 65^2
1089 + 3136 = 4225
4225 = 4225.......correct...so YES, this is a right triangle

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3 years ago

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bekas [8.4K]

Answer:

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Step-by-step explanation:

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Notes:

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3 years ago

G(x) = -2x^3 – 15x^2 + 36x

shusha [124]

Consider the function $G(x) = -2x^3 - 15x^2 + 36x.$ First, factor it:

$G(x) = -2x^3 - 15x^2 + 36x=-x(2x^2+15x-36)=\\ \\=-x\cdot 2\cdot \left(x-\dfrac{-15-\sqrt{513}}{4}\right)\cdot \left(x-\dfrac{-15+\sqrt{513}}{4}\right).$

The x-intercepts are at points $\left(\dfrac{-15-\sqrt{513} }{4},0\right),\ (0,0),\ \left(\dfrac{-15+\sqrt{513} }{4},0\right).$

1. From the attached graph you can see that

function is positive for $x\in \left(-\infrty, \dfrac{-15-\sqrt{513} }{4}\right)\cup \left(0,\dfrac{-15+\sqrt{513} }{4}\right);$
function is negative for $x\in \left(\dfrac{-15-\sqrt{513} }{4},0\right)\cup \left(\dfrac{-15+\sqrt{513} }{4},\infty\right).$

2. Since

$G(-x) = -2(-x)^3 - 15(-x)^2 + 36(-x)=2x^3-15x^2-36x\neq G(x)\ \text{and }\neq -G(x)$ the function is neither even nor odd.

3. The domain is $x\in (-\infty,\infty),$ the range is $y\in (-\infty,\infty).$

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3 years ago

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