Answer:
The radius of circle B is 6 times greater than the radius of circle A
The area of circle B is 36 times greater than the area of circle A
Step-by-step explanation:
we have
<em>Circle A</em>
![D=6\ cm](https://tex.z-dn.net/?f=D%3D6%5C%20cm)
The radius of circle A is
-----> the radius is half the diameter
<em>Circle B</em>
![r=18\ cm](https://tex.z-dn.net/?f=r%3D18%5C%20cm)
Compare the radius of both circles
![3\ cm< 18\ cm](https://tex.z-dn.net/?f=3%5C%20cm%3C%2018%5C%20cm)
![18=6(3)](https://tex.z-dn.net/?f=18%3D6%283%29)
The radius of circle B is six times greater than the radius of circle A
Remember that , if two figures are similar, then the ratio of its areas is equal to the scale factor squared
All circles are similar
In this problem the scale factor is 6
so
![6^{2}=36](https://tex.z-dn.net/?f=6%5E%7B2%7D%3D36)
therefore
The area of circle B is 36 times greater than the area of circle A
Since it is an equilateral triangle, all of the sides are the same length.
So, x=14 :)
Hope this helps!
Answer:
Step-by-step explanation:
sec x( cotx + cos x )= csc x+ 1
1/cos x( cosx/ sinx +cosx) = csc x+ 1
1/cosx ( cosx + sinxcosx/sinx) = csc x+ 1
1/cosx( cosx) ( 1+sinx/sinx) = csc x+ 1
1(1/sinx+1) = csc x+ 1
cscx +1= = csc x+ 1
![- 15x( - 7) = 105x](https://tex.z-dn.net/?f=%20-%2015x%28%20-%207%29%20%3D%20%20105x)
Not much more to say about this. Just multiply the integer by the coefficient.