Answer: 18.7
Step-by-step explanation:
Find the lengths of AB, BC, and CA
AB = 
= 5
≈ 7.1
BC = 
= 5 ≈ 7.1
CA = 
= 2
≈ 4.5
7.1 + 7.1 + 4.5 = 18.7
18 - (8 - 3 • (2t + 5)) = 0
6t + 25 = 0
3.1 Solve : 6t+25 = 0
Subtract 25 from both sides of the equation :
6t = -25
Divide both sides of the equation by 6:
t = -25/6 = -4.167
Final answer is
t = -25/6 = -4.167
The correct answer is: [B]: "40 yd² " .
_____________________________________________________
First, find the area of the triangle:
The formula of the area of a triangle, "A":
A = (1/2) * b * h ;
in which: " A = area (in units 'squared') ; in our case, " yd² " ;
" b = base length" = 6 yd.
" h = perpendicular height" = "(4 yd + 4 yd)" = 8 yd.
___________________________________________________
→ A = (1/2) * b * h = (1/2) * (6 yd) * (8 yd) = (1/2) * (6) * (8) * (yd²) ;
= " 24 yd² " .
___________________________________________________
Now, find the area, "A", of the square:
The formula for the area, "A" of a square:
A = s² ;
in which: "A = area (in "units squared") ; in our case, " yd² " ;
"s = side length (since a 'square' has all FOUR (4) equal side lengths);
A = s² = (4 yd)² = 4² * yd² = "16 yd² "
_________________________________________________
Now, we add the areas of BOTH the triangle AND the square:
_________________________________________________
→ " 24 yd² + 16 yd² " ;
to get: " 40 yd² " ; which is: Answer choice: [B]: " 40 yd² " .
_________________________________________________
I would say 50/50 chance because it can go ether ways one can go heads the others can go tails
