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Bad White [126]
2 years ago
12

3/8 of 24 is equal to?​

Mathematics
2 answers:
o-na [289]2 years ago
8 0

Answer:

9

Step-by-step explanation:

mixer [17]2 years ago
4 0

9, this is because 3/8 × 24 = 9

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Instead of using the values {1,2,3,4,5,6} on dice, suppose a pair of dice have the following: {1,2,2,3,3,4} on one die and {1,3,
ozzi

Step-by-step explanation:

Sample space, S = {(1,1),(1,3),(1,4),(1,5),(1,6),(1,8),(2,1),(2,3),(2,4),(2,5),(2,6),(2,8),(2,1),(2,3),(2,4),(2,5),(2,6),(2,8),(3,1),(3,3),(3,4),(3,5),(3,6),(3,8),(3,1),(3,3),(3,4),(3,5),(3,6),(3,8),(4,1),(4,3),(4,4),(4,5),(4,6),(4,8)}

These dice will give a sum of 2 with N={(1,1)}, which only has 1 combination

Thus, the probability of rolling a sum of 2 with these dice is

\frac{1}{36}

8 0
3 years ago
If two standard six-sided dice are tossed, what is the probability that a 5 is rolled on at least one of the two dice? express y
zaharov [31]
We define the probability of a particular event occurring as:
\frac{number\ of \ desired\ outcomes}{number\ of\ possible\ outcomes}

What are the total number of possible outcomes for the rolling of two dice? The rolls - though performed at the same time - are <em>independent</em>, which means one roll has no effect on the other. There are six possible outcomes for the first die, and for <em>each </em>of those, there are six possible outcomes for the second, for a total of 6 x 6 = 36 possible rolls.

Now that we've found the number of possible outcomes, we need to find the number of <em>desired</em> outcomes. What are our desired outcomes in this problem? They are asking for all outcomes where there is <em>at least one 5 rolled</em>. It turns out, there are only 3:

(1) D1 - 5, D2 - Anything else, (2), D1 - Anything else, D2 - 5, and (3) D1 - 5, D2 - 5

So, we have \frac{3}{36} = \frac{1}{12} probability of rolling at least one 5.
6 0
3 years ago
Plz helpppp I don’t GET THIS
Liono4ka [1.6K]
First you have to find 1/3 of the marbles. That means in the twelve marvels she has, there are three even groups. Divide twelve by three and you get four. So if each group is four, it is simple from here on out. If she started out with twelve and she lost 1/3 of them(4) it would be 12-4. You know this because lost is another for for subtract. 12-4=8. She has 8 marbles left.
6 0
3 years ago
Read 2 more answers
Brenda does household chores for neighbors to earn spending money. One week she worked 312 hours for $4.75 an hour, 6 hours and
Amiraneli [1.4K]

Answer:76

Step-by-step explanation:

8 0
3 years ago
How do I solve these problems? ln(x) = 5.6 + ln(7.5) and log(x) = 5.6 - log(7.5)
SOVA2 [1]

Use the rules of logarithms and the rules of exponents.

... ln(ab) = ln(a) + ln(b)

... e^ln(a) = a

... (a^b)·(a^c) = a^(b+c)

_____

1) Use the second rule and take the antilog.

... e^ln(x) = x = e^(5.6 + ln(7.5))

... x = (e^5.6)·(e^ln(7.5)) . . . . . . use the rule of exponents

... x = 7.5·e^5.6 . . . . . . . . . . . . use the second rule of logarithms

... x ≈ 2028.2 . . . . . . . . . . . . . use your calculator (could do this after the 1st step)

2) Similar to the previous problem, except base-10 logs are involved.

... x = 10^(5.6 -log(7.5)) . . . . . take the antilog. Could evaluate now.

... = (1/7.5)·10^5.6 . . . . . . . . . . of course, 10^(-log(7.5)) = 7.5^-1 = 1/7.5

... x ≈ 53,080.96

8 0
3 years ago
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