Write log(x^2-9)-log(x+3) as a single logarithm.

2 answers:

5 0

One way: log(A)-log(B) = log(A/B) right?

So, log( x^2-9/(x+3))

Now x^2-9 = (x+3)*(x-3), and x^2-9/(x+3) = x-3,

so log(x^2-9)-log(x+3) = log(x-3),

Indeed for all x but for x = -3, but probably no one asks you about that detail?

Tresset [83]2 years ago

5 0

Answer:

b edge

Step-by-step explanation:

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