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2 years ago

Write log(x^2-9)-log(x+3) as a single logarithm.

2 answers:

5 0

One way: log(A)-log(B) = log(A/B) right?

So, log( x^2-9/(x+3))

Now x^2-9 = (x+3)*(x-3), and x^2-9/(x+3) = x-3,

so log(x^2-9)-log(x+3) = log(x-3),

Indeed for all x but for x = -3, but probably no one asks you about that detail?

Tresset [83]2 years ago

5 0

Answer:

b edge

Step-by-step explanation:

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3 years ago

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2 years ago

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Step-by-step explanation:

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3 years ago

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Which expression has a value of 15 when p = 12?

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Step-by-step explanation:

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2 years ago

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A research team at Cornell University conducted a study showing that approximately 10% of all businessmen who wear ties wear the

LenKa [72]

Answer:

a) The probability that at least 5 ties are too tight is P=0.0432.

b) The probability that at most 12 ties are too tight is P=1.

Step-by-step explanation:

In this problem, we could represent the proabilities of this events with the Binomial distirbution, with parameter p=0.1 and sample size n=20.

a) We can express the probability that at least 5 ties are too tight as:

$P(x\geq5)=1-\sum\limits^4_{k=0} {\frac{n!}{k!(n-k)!} p^k(1-p)^{n-k}}\\\\P(x\geq5)=1-(0.1216+0.2702+0.2852+0.1901+0.0898)\\\\P(x\geq5)=1-0.9568=0.0432$

The probability that at least 5 ties are too tight is P=0.0432.

a) We can express the probability that at most 12 ties are too tight as:

$P(x\leq 12)=\sum\limits^{12}_{k=0} {\frac{n!}{k!(n-k)!} p^k(1-p)^{n-k}}\\\\P(x\leq 12)=0.1216+0.2702+0.2852+0.1901+0.0898+0.0319+0.0089+0.0020+0.0004+0.0001+0.0000+0.0000+0.0000\\\\P(x\leq 12)=1$

The probability that at most 12 ties are too tight is P=1.

5 0

2 years ago