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Juliette [100K]
3 years ago
10

Write log(x^2-9)-log(x+3) as a single logarithm.

Mathematics
2 answers:
AfilCa [17]3 years ago
5 0
One way: log(A)-log(B) = log(A/B) right?

So, log( x^2-9/(x+3))

Now x^2-9 = (x+3)*(x-3), and x^2-9/(x+3) = x-3,

so log(x^2-9)-log(x+3) = log(x-3),

Indeed for all x but for x = -3, but probably no one asks you about that detail?
Tresset [83]3 years ago
5 0

Answer:

b edge

Step-by-step explanation:

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What is the range of the function graphed below?<br> A. 1_ B. -3 C. -2_ D. -3_
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The product of two consecutive even integers is 288 find the integers.
algol [13]
Using algebra
n and n+2 are the integers
n*(n+2)=288
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288=2*2*2*2*2*3*3=(2*2*2*2)*(2*3*3)=16*18 and 18-16=2
factor(n+18)(n-16)=0
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this is one solution
n-16=0
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this is another solution
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