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Juliette [100K]
3 years ago
10

Write log(x^2-9)-log(x+3) as a single logarithm.

Mathematics
2 answers:
AfilCa [17]3 years ago
5 0
One way: log(A)-log(B) = log(A/B) right?

So, log( x^2-9/(x+3))

Now x^2-9 = (x+3)*(x-3), and x^2-9/(x+3) = x-3,

so log(x^2-9)-log(x+3) = log(x-3),

Indeed for all x but for x = -3, but probably no one asks you about that detail?
Tresset [83]3 years ago
5 0

Answer:

b edge

Step-by-step explanation:

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Substitute these values into equation (i) as follows;

d = |\frac{((1*5) + (1*0) + (1 * (-6)) - 6)}{\sqrt{1^2 + 1^2 + 1^2}} |

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d = |\frac{(-7)}{\sqrt{3}} |

d = \frac{7}{\sqrt{3}}

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