a.
h = 2c - 3
b.
3h + 1.5c = 201
c.
We have a system of equations from part a and b.
h = 2c - 3 (equation 1)
3h + 1.5c = 201 (equation 2)
We use substitution method to solve this system.
Substitute equation 1 in equation 2 to get
3h + 1.5c = 201
>> 3(2c - 3) + 1.5c = 201
>> 6c - 9 + 1.5c = 201
>> 7.5c = 201 + 9
>> 7.5c = 210
>> c = 210 / 7.5
>> c = 28
Plug this value back in equation 1 to get
h = 2c - 3
>> h = 2(28) - 3 = 56 - 3 = 53
So, c = 28 and h = 53 implies that <u>28 corndogs</u> and 53 hotdogs were sold.
Answer:
the appropriate choice is the last one
Step-by-step explanation:
![7^{\frac{4}{5}}=(7^4)^{\frac{1}{5}}=\sqrt[5]{7^4}](https://tex.z-dn.net/?f=7%5E%7B%5Cfrac%7B4%7D%7B5%7D%7D%3D%287%5E4%29%5E%7B%5Cfrac%7B1%7D%7B5%7D%7D%3D%5Csqrt%5B5%5D%7B7%5E4%7D)
This is equivalent to b^(pq) with b=7, p=4, q=1/5. Here, q is a rational number, as suggested by the last answer choice.
Answer:
It's exponential growth.
Step-by-step explanation:
b/c any value of b that's greater than 1 is an exponential growth function, and anything that's 0<b<1 or if b<0, the function would be an exponential decay.
Weekly income = 70...she budgets 40 for movies and food.....70 - 40 = 30...that leaves 30 per week that she saves.
1 month = 4 weeks....so 6 months = (6 * 4) = 24 weeks
24 weeks....saving 30 per week = (24 * 30) = $ 720 <===
Good to see you here. Now back to the train.
Kaduna, K Lagos, L
Train leaves at 64 km/h
One hour late second train leaves Lagos at 96 km/h.
At the point they meet, if first train has been travelling for "x" hours. Second train has been travelling for (x-1) hour.
At the point the meet, the total distance travelled is equal to 624 km.
Therefore:
64(x) + 96(x-1) = 624
64x + 96x - 96 = 624
160x = 624+96
160x = 720 , x = 720/160 = 4.5
So when they meet, the first train which left Kaduna has travelled= 64x = 64*4.5= 288km from Kaduna.
So it is (624-288) km from Lagos. = 336 Km from Lagos.
Second train which left Lagos has travelled = 96(x-1) = 96(4.5-1) = 336km.
The second train is also 336 km away from Lagos.
Cheers.