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svetoff [14.1K]
3 years ago
11

Stephanie sells 12 pretzels per hour. Robert sells 15 pretzels per hour. This week, Robert sold an additional 18 pretzels. Which

of the following expressions represent the total sales of both people in this week, where S represents Stephanie worked and R represents the number of hours that Robert worked?
A- 15S + 12R +18
B- 12S + 15R +18
C- 12S + 15R
D- 12S + 18R
Mathematics
1 answer:
Aleonysh [2.5K]3 years ago
5 0

Answer:

I'm pretty sure it is D I'm not 100% sure though... sorry if it is wrong

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A calculator displays a result as 1.3540980 107 kg. the estimated uncertainty in the result is ±2%. how many digits should be i
yan [13]
<span>2 significant digits.
       
Let's see what the range of possible values you can have for 1.3540980 if your uncertainty is +/- 2% 2% of 1.3540980 = 0.02 * 1.3540980 = 0.027082 So the lowest possible value for your result is 1.3540980 - 0.027082 = 1.327016 The largest possible result is 1.3540980 + 0.027082 = 1.38117996 Notice that only the 1st 2 digits of the result match which is reasonable since a 2% error means that your result is only accurate to within 1 part in 50.</span>
3 0
3 years ago
Big chickens: The weights of broilers (commercially raised chickens) are approximately normally distributed with mean 1387 grams
Nataliya [291]

Answer:

a) 0.2318

b) 0.2609

c) No it is not unusual for a broiler to weigh more than 1610 grams

Step-by-step explanation:

We solve using z score formula

z-score is is z = (x-μ)/σ, where x is the raw score, μ is the population mean, and σ is the population standard deviation.

Mean 1387 grams and standard deviation 192 grams. Use the TI-84 Plus calculator to answer the following.

(a) What proportion of broilers weigh between 1150 and 1308 grams?

For 1150 grams

z = 1150 - 1387/192

= -1.23438

Probability value from Z-Table:

P(x = 1150) = 0.10853

For 1308 grams

z = 1308 - 1387/192

= -0.41146

Probability value from Z-Table:

P(x = 1308) = 0.34037

Proportion of broilers weigh between 1150 and 1308 grams is:

P(x = 1308) - P(x = 1150)

0.34037 - 0.10853

= 0.23184

≈ 0.2318

(b) What is the probability that a randomly selected broiler weighs more than 1510 grams?

1510 - 1387/192

= 0.64063

Probabilty value from Z-Table:

P(x<1510) = 0.73912

P(x>1510) = 1 - P(x<1510) = 0.26088

≈ 0.2609

(c) Is it unusual for a broiler to weigh more than 1610 grams?

1610- 1387/192

= 1.16146

Probability value from Z-Table:

P(x<1610) = 0.87727

P(x>1610) = 1 - P(x<1610) = 0.12273

≈ 0.1227

No it is not unusual for a broiler to weigh more than 1610 grams

8 0
3 years ago
1/2(2g-3)=-4(g+1) show work
brilliants [131]
1g-1.5=-4g-4 (distribute 1/2 and -4 inside their respective parenthesis)
1g=-4g-2.5 (add 1.5 to -4)
5g=-2.5 (add 4g to 1g)
g=-0.5 (divide both sides by 5)
7 0
3 years ago
Evaluate t-u/v when t=2 u=(-8) v(-1/2)
Dovator [93]
Simple, plug n chug...

t- \frac{u}{v}

t=2

u=-8

v=-0.5

Now, plug in what you have,

2- \frac{-8}{-0.5}

\frac{-8}{-0.5} =16

Now,

2-16=-14

Thus, your answer, -14.
5 0
2 years ago
Suppose Johnny invests $41,745 into an account, which has been earning interest for many years and he now has a total of $39,974
Dmitriy789 [7]

Answer:

A negative number would be reasonable in the solution of the rate of the investment. It would be reasonable because Johnny started out with $41,745 in his account and ended up with $39,974 which means that the rate has to be negative.


please rate and thank : )


7 0
2 years ago
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