Need help with this question asap

Sveta_85 [38]

1) Find the value of x and y.

2) Then use the Order of Operations to help you out with the computation.

6 0

2 years ago

The probability that a high school student in in the marching band is 0.47. The probability that a student plays a varsity sport

IrinaK [193]

The probability that a high school student in in the marching band is 0.47

so, $P(M)=0.47$

The probability that a student plays a varsity sport is 0.32

so, $P(V)=0.32$

the probability that a student is in the marching band and plays a varsity sport is 0.24

so, we get

P(M∩V)=0.24

a student plays a varsity sport if we know she is in the marching band

so,

P(V|M)=(P(V∩M))/(P(M))

now, we can plug values

and we get

$P(V|M)=\frac{0.24}{0.47}$

$P(V|M)=0.51063$

So,

the probability that a student plays a varsity sport if we know she is in the marching band is 0.51063......Answer

8 0

2 years ago

Read 2 more answers

There is a bag filled with 3 blue and 4 red marbles.

tresset_1 [31]

Using the hypergeometric distribution, it is found that there is a 0.4286 = 42.86% probability of getting 2 of the same colour.

The marbles are chosen without replacement, hence the <em>hypergeometric </em>distribution is used to solve this question.

<h3>What is the hypergeometric distribution formula?</h3>

The formula is:

$P(X = x) = h(x,N,n,k) = \frac{C_{k,x}C_{N-k,n-x}}{C_{N,n}}$

$C_{n,x} = \frac{n!}{x!(n-x)!}$

The parameters are:

x is the number of successes.

N is the size of the population.

n is the size of the sample.

k is the total number of desired outcomes.

In this problem:

There is a total of 3 + 4 = 7 marbles, hence N = 7.

Of those, 3 are blue, hence k = 3.

2 marbles will be taken, hence n = 2.

The probability of getting 2 of the same colour is the sum of P(X = 0), which is both red, with P(X = 2), which is both blue, then:

$P(X = x) = h(x,N,n,k) = \frac{C_{k,x}C_{N-k,n-x}}{C_{N,n}}$

$P(X = 0) = h(0,7,2,3) = \frac{C_{3,0}C_{4,2}}{C_{7,2}} = 0.2857$

$P(X = 2) = h(2,7,2,3) = \frac{C_{3,2}C_{4,0}}{C_{7,2}} = 0.1429$

Hence:

$p = P(X = 0) + P(X = 2) = 0.2857 + 0.1429 = 0.4286$

0.4286 = 42.86% probability of getting 2 of the same colour.

You can learn more about the hypergeometric distribution at brainly.com/question/4818951

3 0

1 year ago

4> Solve by using Laplace transform: y'+5y'+4y=0; y(0)=3 y'(o)=o

harina [27]

Answer:

$y=3e^{-4t}$

Step-by-step explanation:

$y''+5y'+4y=0$

Applying the Laplace transform:

$\mathcal{L}[y'']+5\mathcal{L}[y']+4\mathcal{L}[y']=0$

With the formulas:

$\mathcal{L}[y'']=s^2\mathcal{L}[y]-y(0)s-y'(0)$

$\mathcal{L}[y']=s\mathcal{L}[y]-y(0)$

$\mathcal{L}[x]=L$

$s^2L-3s+5sL-3+4L=0$

Solving for $L$

$L(s^2+5s+4)=3s+3$

$L=\frac{3s+3}{s^2+5s+4}$

$L=\frac{3(s+1)}{(s+1)(s+4)}$

$L=\frac3{s+4}$

Apply the inverse Laplace transform with this formula:

$\mathcal{L}^{-1}[\frac1{s-a}]=e^{at}$

$y=3\mathcal{L}^{-1}[\frac1{s+4}]=3e^{-4t}$

7 0

2 years ago

Find the mean, median and mode of the given data? 8, 10,11, 8, 14,18, 8, 10, 11, 8, 15

Inessa05 [86]

Answer:

it might be 18 ❤

Step-by-step explanation:

I'm pretty sure it is 18 let me know

5 0

1 year ago