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andrey2020 [161]
3 years ago
10

Neeed help please???????!!!!!!

Mathematics
1 answer:
irakobra [83]3 years ago
3 0
Arc HKJ for one but I do known abt 2
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If f(x)=2x+sinx and the function g is the inverse of f then g'(2)=
Alexxx [7]
\bf f(x)=y=2x+sin(x)
\\\\\\
inverse\implies x=2y+sin(y)\leftarrow f^{-1}(x)\leftarrow g(x)
\\\\\\
\textit{now, the "y" in the inverse, is really just g(x)}
\\\\\\
\textit{so, we can write it as }x=2g(x)+sin[g(x)]\\\\
-----------------------------\\\\

\bf \textit{let's use implicit differentiation}\\\\
1=2\cfrac{dg(x)}{dx}+cos[g(x)]\cdot \cfrac{dg(x)}{dx}\impliedby \textit{common factor}
\\\\\\
1=\cfrac{dg(x)}{dx}[2+cos[g(x)]]\implies \cfrac{1}{[2+cos[g(x)]]}=\cfrac{dg(x)}{dx}=g'(x)\\\\
-----------------------------\\\\
g'(2)=\cfrac{1}{2+cos[g(2)]}

now, if we just knew what g(2)  is, we'd be golden, however, we dunno

BUT, recall, g(x) is the inverse of f(x), meaning, all domain for f(x) is really the range of g(x) and, the range for f(x), is the domain for g(x)

for inverse expressions, the domain and range is the same as the original, just switched over

so, g(2) = some range value
that  means if we use that value in f(x),   f( some range value) = 2

so... in short, instead of getting the range from g(2), let's get the domain of f(x) IF the range is 2

thus    2 = 2x+sin(x)

\bf 2=2x+sin(x)\implies 0=2x+sin(x)-2
\\\\\\
-----------------------------\\\\
g'(2)=\cfrac{1}{2+cos[g(2)]}\implies g'(2)=\cfrac{1}{2+cos[2x+sin(x)-2]}

hmmm I was looking for some constant value... but hmm, not sure there is one, so I think that'd be it
5 0
3 years ago
29 If the zeros of a quadratic function, F, are -3 and 5, what is the equation of the axis of symmetry
UNO [17]

Answer:

the axis of symmetry is X = 1

Step-by-step explanation:

make sure to ask if you need any further guidance.

8 0
2 years ago
Find the value of the missing variables which are M, A, and X
Mars2501 [29]

Answer:

m=5 , a=3 x= 3 you get that by looking at the other numbers that they provided.

3 0
3 years ago
!!!! PLEASEEE HELP ME, IDK WHAT TO DO PLEASE !!!!
Helga [31]

Answer:

  The first question is A.

  The second question is C.

   The thid question is B., I think i'm not quit sure sorry

4 0
3 years ago
Solve -2.5n + 8.7 > 5.45.
AlexFokin [52]
A. n<1.3

-2.5n+8.7>5.45
subtract 8.7 from both sides
-2.5n>-3.25
divide -2.5 from both sides 
(since you divided by a negative you flip the sign!!)
n<1.3


5 0
3 years ago
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