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Sholpan [36]
3 years ago
11

The electronics store would pay him $9 per hour towork 15hrs per week and 3.5% commission on his sales the average weekly sales

are $7,000 how much will he make selling electronics
Mathematics
1 answer:
ryzh [129]3 years ago
6 0
First, find out his wage
15 hours×$9= $135

Next find his commission
$7000×3.5%
=7000×0.035
=$245

Finally, add these together
$135+$245
=$380 He will make $380 selling electronics per week
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Y varies directly with x and y = 12 when x =5 what is the value of y when x = 8
torisob [31]
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4 years ago
How many integers between 10000 and 99999, inclusive, are divisible by 3 or<br> 5 or 7?
Yuki888 [10]

Answer: Hence, there are approximately 48884 integers are divisible by 3 or 5 or 7.

Step-by-step explanation:

Since we have given that

Integers between 10000 and 99999 = 99999-10000+1=90000

n( divisible by 3) = \dfrac{90000}{3}=30000

n( divisible by 5) = \dfrac{90000}{5}=18000

n( divisible by 7) = \dfrac{90000}{7}=12857.14

n( divisible by 3 and 5) = n(3∩5)=\dfrac{90000}{15}=6000

n( divisible by 5 and 7) = n(5∩7) = \dfrac{90000}{35}=2571.42

n( divisible by 3 and 7) = n(3∩7) = \dfrac{90000}{21}=4285.71

n( divisible by 3,5 and 7) = n(3∩5∩7) = \dfrac{90000}{105}=857.14

As we know the formula,

n(3∪5∪7)=n(3)+n(5)+n(7)-n(3∩5)-n(5∩7)-n(3∩7)+n(3∩5∩7)

=30000+18000+12857.14-6000-2571.42-4258.71+857.14\\\\=48884.15

Hence, there are approximately 48884 integers are divisible by 3 or 5 or 7.

5 0
4 years ago
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