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poizon [28]
3 years ago
7

Write the equation for an ellipse with the center at the origin, a vertical major axis of length 30, and a horizontal minor axis

of length 16.

Mathematics
2 answers:
velikii [3]3 years ago
7 0

Answer:

C

Step-by-step explanation:

hope that helps

goldfiish [28.3K]3 years ago
5 0

Answer:

B

Step-by-step explanation:

a = 30    b = 16

x²/b² + y²/a² = 1

x²/16² + y²/30² = 1

x²/256 + y²/900 = 1

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5 0
3 years ago
Consider the set of differences, denoted with d, between two dependent sets: 84, 85, 83, 63, 61, 100, 98. Find the sample standa
sveta [45]

Answer:

The sample standard deviation is 15.3.

Step-by-step explanation:

Given data items,

84, 85, 83, 63, 61, 100, 98,

Number of data items, N = 7,

Let x represents the data item,

Mean of the data points,

\bar{x}=\frac{84+85+83+63+61+100+98}{7}

=82

Hence, sample standard deviation would be,

\sigma= \sqrt{\frac{1}{N-1}\sum_{i=1}^{N} (x_i-\bar{x})^2}

=\sqrt{\frac{1}{6}\sum_{i=1}^{7} (x_i-82)^2}

=\sqrt{\frac{1}{6}\times 1396}

=\sqrt{232.666666667}

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4 0
2 years ago
If you deposit $12,500 in an account that pays 4.5% interest quarterly, what is the balance after 8 years? How much did the acco
Masja [62]

In order to determine the balance of the account, use the following formula for the amount of money obtained after t years, basen on a compound interest:

A=P(1+\frac{r}{n})^{nt}

where,

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A: amount earnt after t years = ?

r: interest rate in decimal form = 0.045 (4.5%)

n: times at year for the compund interes = 4 (quaterly)

Replace the previous values of the parameters into the formula for A and simplify:

\begin{gathered} A=12,500(1+\frac{0.045}{4})^{4\cdot8} \\ A=12,500(1+0.01125)^{32} \\ A=12,500(1.01125)^{32} \\ A=12,500(1.430451402) \\ A\approx17,880.64 \end{gathered}

Hence, the balance after 8 years is approximately $17,880.64 in the account.

The interest earnt by the account is given by the difference between the previous result and the principal invesment:

I = $17,880.64 - $12,500 = $5,380.64

Hence, the interest earnt is $5,380.64

3 0
1 year ago
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