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3 years ago

What is a decimal that is equivalent to the fraction 8/10 ? Enter the answer in the box.

Mathematics

2 answers:

N76 [4]3 years ago

5 0

Answer:

0.8

Step-by-step explanation:

belka [17]3 years ago

4 0

Answer:

Step-by-step explanation:

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Find the solutions to the equation below.<br> Check all that apply.<br> 4x2 + 4x + 1 = 0

Verizon [17]

Answer:

The solution for the given polynomial $4x^2 + 4x+ 1 = 0$ is $x = (\frac{-1}{2})$

Step-by-step explanation:

Here, the given quadratic equation is : $4x^2 + 4x+ 1 = 0$

Now, here solving the given equation by SPLITTING THE MIDDLE TERM:

$4x^2 + 4x+ 1 = 0 = 4x^2 + 2x+ 2x + 1 = 0\\\implies 2x( 2x + 1) + 1(2x + 1) = 0\\\implies (2x +1)(2x +1) = 0\\$

⇒ either (2x+1) = 0, or ( 2x + 1) = 0

⇒ x = -1/2 or x = -1/2

Here, in both the cases, the value of x is equal i.e x = -1/2

So, the given function has TWO IDENTICAL ROOTS.

Hence the solution for the given polynomial $4x^2 + 4x+ 1 = 0$ is $x = (\frac{-1}{2})$

4 0

3 years ago

PLEASE PLEASE HELP ME

andreyandreev [35.5K]

Answer:

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

What is the value of X? Make sure to show all of your work! Hint: What does each angle measure in an equilateral triangle? You d

Bogdan [553]

Answer: X = 9

Show Your Work:
All Angles & Sides = 60.
All Triangles = 180.
60 x 3 = 180.

Angle N:
7x - 3 = 60
7 * 9 - 3 = 60.

5 0

3 years ago

How do you solve 3/2÷1\4=n then n is in between

insens350 [35]

Your answer is n = 6

3 0

3 years ago

Given the volume of Figure A is 512cm ^3and Figure B is 343cm^3, find the ratio of the perimeter from Figure A to Figure B.

sp2606 [1]

$\bf ~\hspace{5em} \textit{ratio relations of two similar shapes} \\[2em] \begin{array}{ccccllll} &\stackrel{ratio~of~the}{Sides}&\stackrel{ratio~of~the}{Areas}&\stackrel{ratio~of~the}{Volumes}\\ \cline{2-4}&\\ \cfrac{\textit{similar shape}}{\textit{similar shape}}&\cfrac{s}{s}&\cfrac{s^2}{s^2}&\cfrac{s^3}{s^3} \end{array}\\\\[-0.35em] ~\dotfill$

$\bf \cfrac{\textit{similar shape}}{\textit{similar shape}}\qquad \cfrac{s}{s}=\cfrac{\sqrt{Area}}{\sqrt{Area}}=\cfrac{\sqrt[3]{Volume}}{\sqrt[3]{Volume}} \\\\[-0.35em] \rule{34em}{0.25pt}$

$\bf \cfrac{\textit{figure A}}{\textit{figure B}}\qquad \qquad \cfrac{s}{s}=\cfrac{\sqrt[3]{512}}{\sqrt[3]{343}}\qquad \begin{cases} 512=&2^9\\ &2^{3\cdot 3}\\ &(2^3)^3\\ 343=&7^3 \end{cases}\implies \cfrac{s}{s}=\cfrac{\sqrt[3]{(2^3)^3}}{\sqrt[3]{7^3}} \\\\\\ \cfrac{s}{s}=\cfrac{2^3}{7}\implies \cfrac{s}{s}=\cfrac{8}{7}\implies s:s = 8:7\impliedby \textit{ratio of the }\stackrel{sides~and}{perimeters}$

5 0

3 years ago