Step-by-step explanation:
lo siento much solo si fuera Buena con matimaticas.
Answer:
-6.134 to +6.134
Step-by-step explanation:
given that a large population of variable x is characterized by its known mean value of 6.1 units and a standard deviation of 1.0 units and a normal distribution
X is Normal with mean =6.1 and std dev = 1 unit
We are to determine the range of values containing 70% of the population of x
We know that normal distribution curve is bell shaped symmetrical about the mean.
So to find 70% range we can use 35% on either side of the mean
Using std normal distribution table the value of z for which probability from 0 to z is 0.35 is 1.034
Hence corresponding x value is

i.e. 70% values lie between
-6.134 to +6.134
(a) m<IJK = 90 since segment IK is a diameter
(b) KI = 10 since since LM = KM = KI = 5. The 3 segments are radii.
(c) EP * PL = OP * PF; EP = 2
(d) m<OFH = 178/2 = 89; inscribed angle is half measure of intercepted arc
2x+y-10=0
2x+y=10 ------------------->(1)
x-y-5=0
x-y=5------------------------>(2)
(1)+(2); 3x=15
x= 5
(x=5) substitute in (1); y=0