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Nikolay [14]
3 years ago
12

A homeowner wants several small dormers built on his roof to admit light. They will be in the shape of isosceles triangles whose

sides will exceed their base by 5 in. If the perimeter is 100 in., what are the lengths of the three sides? The base is and the equal sides are .
Mathematics
1 answer:
Vlad1618 [11]3 years ago
4 0
P = s + (s + 5) + (s + 5) This represents the two sides that are 5 inches longer than the base (s + 5) and the base (s).
Simplifying.
100 = 3s + 10
subtract 10 from both sides
 90 = 3s
divide both sides by 3
30 = s
base = 30
sides = 35

CHECK 30 + 35 + 35 = 100

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Xpressions equivalent to 7 3/4 + 3 5/6 - 1 3/4
user100 [1]

Answer:

125/6

(Decimal: 20.833333)

Step-by-step explanation:

3 0
2 years ago
Hi please i nedd help with these questions .
Vlad1618 [11]

Answer:

Step-by-step explanation:

#1:

\frac{18m^2u}{16n^3v^2} \div \frac{24m}{15nu^3}*\frac{8n^2v^3}{30m^3u}

division sign means that we flip the fraction

\frac{18m^2u}{16n^3v^2} * \frac{15nu^3}{24m}*\frac{8n^2v^3}{30m^3u}

now we can multiply all the constants together and all variables

m: (m^2)/(m*m^4) = (m^2)/(m^4) = 1/(m^2)\\u: (u * u^3)/(u) = (u^4)/(u) = u^3\\n: (n*n^2)/(n^3) = 1\\v: (v^3) / (v^2) = v\\(18*15*8)/(16*24*30) = \frac{3}{16}

now we can combine all the parts

\frac{3u^3v}{16m^2}

#2:

\frac{24a^2b^3c}{9bc^3}\div\frac{4a^5bc^3}{27a^3b^2c}

\frac{24a^2b^3c}{9bc^3}*\frac{27a^3b^2c}{4a^5bc^3}

a: (a^2 * a^3)/(a^5) = 1\\b: (b^3 *b^2)/(b*b) = b^3\\c: (c*c)/(c^3*c^3)= 1/(c^4)\\(24*27)/(9*4)= 18

\frac{18b^3}{c^4}

3 0
2 years ago
Read 2 more answers
All of the following are equivalent except _____.<br> 4 · y<br> 4 + y<br> 4y<br> (4)(y)
DENIUS [597]
The answer is: [B]: 4 + y .
______________________
The rest of the answer choices given are all different ways to express, or are equivalents of, the number "4", multiplied by the variable, "y".
______________________
5 0
3 years ago
Read 2 more answers
Please help! PLSSS! Its for a math test.​
Maslowich

Answer:

330(D)

Step-by-step explanation:

So lets go over what we know:

#1: 44 out of 80 people think they have a average fitness level.

#2: 80 out of the 600 people in the school were surveyed.

Using what we know, lets try and find the answer.

So lets divide the total amount of people, by the amount of people that took the survey:

600/80

=

7.5

Ok, so now we know that we need to take 7.5 surveys to find out what all the students think of their fitness level.

Now lets take teh amount of people in a single survey, with average fitness(44), and multpliy it by how many surveys are needed for the whole school(7.5):

44*7.5

=

330

This is the amount of people in the whole school who think they have an average fitness level.

I hope this helps! :)

<u>Answer:</u>

<u>330</u>

8 0
3 years ago
20% of the tickets sold at a water park were adult tickets. If the park sold 55 tickets in all,how many did it sell?
djyliett [7]

Answer:

11 adult tickets

Step-by-step explanation:

I guess you want the number of adult tickets sold.

That is 20% of 55

= 0.20*55

= 11 (answer)

8 0
3 years ago
Read 2 more answers
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