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3 years ago

HELP ME PLEASE!!! GIVEN sin0= √23/12 tan0= √23/11 Find cos0

Mathematics

1 answer:

prohojiy [21]3 years ago

7 0

Answer:

$cos \theta = \frac{11}{12}$

Step-by-step explanation:

$sin \theta = \frac{\sqrt{23}}{12} \ , \ tan \theta = \frac{\sqrt{23}}{11}\\\\tan \theta = \frac{sin \theta }{cos \theta }\\\\ \frac{\sqrt{23}}{11} = \frac{\frac{\sqrt{23}}{12} }{cos \theta}\\\\cos \theta = \frac{\frac{\sqrt{23}}{12} }{\frac{\sqrt{23}}{11} }\\\\cos \theta = \frac{\sqrt{23}}{12 } \times \frac{11}{\sqrt{23}}\\\\cos \theta = \frac{11}{12}$

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