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melomori [17]
3 years ago
14

A dealer marks the price of his mobiles 40% above the cost price and allows 20% discount. If his/her purchase price of a mobile

is Rs 7,500, how much should a customer pay for it with 13% VAT?​
Mathematics
1 answer:
Katena32 [7]3 years ago
5 0

Answer:

$8475

Step-by-step explanation:

13% of 7500 is 975 so i then added 975 7,500 and got $8,475

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Can somebody help me with this problem
Mekhanik [1.2K]
Break the shape into 2 along the perforated line. now you have two rectangular prisms. find the volume of each and add them together to get your answer.

Rectangular prism: length*width*height
RP1) 10*8*14=1120
RP2) 10*10*8=800
total: 1920
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3 years ago
Which of these situations does not have quantities that combine to make 0.
Lostsunrise [7]

Answer:

B. Hikroko earns $20 working concessions at the football game. she earns $20 as as babysitter

Step-by-step explanation:

also the person who keeps deleting all my answers i hope u break your back

4 0
3 years ago
Solve 5y^2+20=80, where y is the real number
soldi70 [24.7K]

Answer:

2√3

Step-by-step explanation:

5y2+20=80

Step 1: Subtract 20 from both sides.

5y^2+20−20=80−20

5y^2=60

Step 2: Divide both sides by 5.

5y^2 /5 = 60/5

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3 0
3 years ago
V-9/10v+6=11(hlp)this problem is confusing.
Valentin [98]
\frac{v-9}{10v+6}=11 \\\\ 11(10v+6)=v-9 \\\\ 110v+66=v-9 \\\\ 110v-v=-9-66 \\\\ 109v= -75 \\\\ \boxed{v=-\frac{75}{109}}
4 0
3 years ago
Read 2 more answers
Can someone that's very good at math please help me?
gtnhenbr [62]

Answer:

35 :

t = 6.25 years

(about 6 years 3 months)

Equation:

t = (1/r)(A/P - 1)

Calculation:

First, converting R percent to r a decimal

r = R/100 = 4%/100 = 0.04 per year,

then, solving our equation

t = (1/0.04)((2500/2000) - 1) = 6.25

t = 6.25 years

The time required to get a total amount, principal plus interest, of $2,500.00 from simple interest on a principal of $2,000.00 at an interest rate of 4% per year is 6.25 years (about 6 years 3 months).

36:

The two distances are the same (out and back), so set them equal.

That is done by having a (rate)(time) equal a (rate)(time).

One time is “x” and the other is “4.8-x.”

One rate is 460 and the other is 500.

460 x = 500 (4.8 -x)

460 x = 2400 - 500x

900 x = 2400

x = 2.5 hours for the slower plane.

4.8- x = 2.3 hours for the faster plane.

8 0
3 years ago
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