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Volgvan
4 years ago
12

Linear or nonlinear?

Mathematics
1 answer:
Mazyrski [523]4 years ago
5 0

This equation would be linear

The reason why this equation would be linear is because there is a constant change in the equation.

The equation is constantly changing by -1/3, and the change doesn't change, it is constant.

When you graph this equation, you would see that the equation would be linear, or a straight line.

Therefore, your answer would be linear:

Answer:

Linear

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In the triangle below, 4/5 represents which ratio?
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Read 2 more answers
What is 6/6 as a sum of fractions in three different ways
s2008m [1.1K]

Step-by-step explanation:

Remember that 6/6 = 1, so we can use that knowledge to our advantage.

1/2 + 1/2 is one of them, because 1/2 + 1/2 = 2/2 = 1.

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5 0
3 years ago
3. A rabbit and turtle are in a race. Is the relationship between distance
frutty [35]

Answer:

The relationship is proportional for the turtle and the equation is Distance = 54*Time

Step-by-step explanation:

Turtle’s run:

Distance (meters) | Time (minutes)

108                        | 2  

405                       | 7.5

540                       | 10

1768.5                   | 32.75

Rabbitt’s run:

Distance (meters) | Time (minutes)

800                       | 1  

900                       | 5

1107.5                    | 20

1524                      | 32.5

The relationship between distance traveled and time is proportional if this equation is satisfied:  

Distance = k*Time or k = Distance/Time

where k is a constant

For the turtle:

108/2 = 405/7.5 = 540/10 = 1768.5/32.75 = 54

Then, the relationship is proportional and the equation is Distance = 54*Time

For the rabbit:

800/ 1 = 800  

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1107.5/20  = 55.375

1524/32.5  = 46.89

Then, the relationship is not proportional.

7 0
3 years ago
Factor 15(2z+1)^3+10(2z+1)^2-25(2z+1)
ELEN [110]
15(2z+1)^3+10(2z+1)^2-25(2z+1)\\\\subtitute\ x=2z+1\\\\15t^3+10t^2-25t=5t\cdot3t^2+5t\cdot2t-5t\cdot5=5t(3t^2+2t-5)\\\\=5t(3t^2-3t+5t-5)=5t[3t(t-1)+5(t-1)]\\\\=5t(t-1)(3t+5)\\\\=5(2z+1)(2z+1-1)[3(2z+1)+5]\\\\=5(2z+1)(2z)(6z+3+5)=5(2z)(2z+1)(6z+8)\\\\=10z(2z+1)(6z+8)=10z(2z+1)(2)(3z+4)\\\\=\boxed{20z(2z+1)(3z+4)}
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4 years ago
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