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fomenos
3 years ago
14

How much interest is earned on an investment of $12,000 at 2.9% compounded daily for eight years

Mathematics
1 answer:
geniusboy [140]3 years ago
8 0

Answer:

$3,113,34

Step-by-step explanation:

The formula for calculating compound interest is

A=P(1+\frac{r}{n})^{nt}

Where

A=the future total value, i.e, the money you will have after t years.

P=the initial deposit.

r=the annual interest rate.

n=the number of times that interest is compounded per year.

t=the number of years the money is saved.

In our case

A is unknown and we will have to calculate it with the formula.

P=$12,000

r=2.9%=0.029

n=365 because the interest is compounded daily and there are 365 days in a year

t=8 years

Applying the formula we get

A=12,000(1+\frac{0.029}{365})^{365\times8}

A=12,000(1+\frac{0.029}{365})^{2,920}

A=12,000(1.000079)^{2,920}

So A=15,113.336

This is the amount of money you would have after 8 years.

Subtracting the initial deposit from this amount we obtain the interest earned I

I=15,113.336-12,000=3,113.336

Rounded to the nearest hundreth

I=$3,113,30

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