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2 years ago

Help me with this one pls

Mathematics

1 answer:

lora16 [44]2 years ago

4 0

<h3> $= \tt{ - 1.3 - ( - 1.9)}$ </h3><h2> $= \green{\boxed{\tt{{ - 1.3 + 1.9}}}}$ </h2><h3> $= 0.6$ </h3>

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Find SP when CP=Rs.400 and proft%=4%

kvasek [131]

Answer:

$\boxed{Selling\ Price = Rs.\ 424}$

Step-by-step explanation:

Cost Price = Rs. 400

Profit = 4 % of Cost Price

=> $\frac{4}{100} * 600$

=> 4 * 6

=> Profit = Rs. 24

Now, Selling Price = Cost Price + Profit

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1 year ago

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PLEASE HURRY IM TIMED!!!

andriy [413]

<u>Answer-</u>

<em>A. Brandon’s sound intensity level is 1/4th as compared to Ahmad’s.</em>

<u>Solution-</u>

Given that, loudness measured in dB is

$L=10\log \frac{I}{I_0}$

Where,

I = Sound intensity,

I₀ = 10⁻¹² and is the least intense sound a human ear can hear

Given in the question,

I₁ = Intensity at Brandon's = 10⁻¹⁰

I₂ = Intensity at Ahmad's = 10⁻⁴

Then,

$L_1=10\log \frac{I_1}{I_0}=10\log \frac{10^{-10}}{10^{-12}}=10\log \frac{1}{10^{-2}}=10\log 10^{2}=2\times10\log 10=20$

$L_2=10\log \frac{I_2}{I_0}=10\log \frac{10^{-4}}{10^{-12}}=10\log \frac{1}{10^{-8}}=10\log 10^{8}=8\times10\log 10=80$

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2 years ago