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3 years ago

Help me with this one pls

Mathematics

1 answer:

lora16 [44]3 years ago

4 0

<h3> $= \tt{ - 1.3 - ( - 1.9)}$ </h3><h2> $= \green{\boxed{\tt{{ - 1.3 + 1.9}}}}$ </h2><h3> $= 0.6$ </h3>

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1. what’s the distance between (-8, -6) and (4, 10)?

charle [14.2K]

Use the formula of a distance between two points:

$d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

$(-8,\ -6),\ (4,\ 10)\\\\d=\sqrt{(4-(-8))^2+(10-(-6))^2}=\sqrt{12^2+16^2}\\\\=\sqrt{144+256}=\sqrt{400}=\boxed{20}\\\\(5,\ 14),\ (-3,\ -9)\\\\d=\sqrt{(-3-5)^2+(-9-14)^2}=\sqrt{(-8)^2+(-23)^2}\\\\=\sqrt{64+529}=\boxed{\sqrt{593}\approx24.35}$

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3 years ago

The prime factorization of 4

Ilia_Sergeevich [38]

Answer:

2²

Step-by-step explanation:

The prime factorization is only prime numbers multiplied

4 is 2(2) which is

2²

4 0

3 years ago

Read 2 more answers

Look at the following number sequence. 3, 7, 11, 15, . . . Based on the pattern, what are the next two terms?

viva [34]

So, if we look at the number pattern, we can see the numbers go up by 4.

The rule is Add 4.

So, to find the next two terms, we would add 4 to the last number shown, which is 15.

15 + 4 = 19

19 + 4 = 23

So, the next two terms are →19← and →23←.

Glad I could help, and good luck!

AnonymousGiantsFan

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3 years ago

Read 2 more answers

123 Savings and Loan charges a monthly fee of $8 on checking accounts and an overdraft protection fee of $33. Neela's check regi

Stells [14]

Based on the calculation below, the balance on Neela's statement is $153.

<h3>How do we calculate the balance on a bank statement?</h3>

The balance on Neela's statement can be calculated using the following formula:

Balance on statement = Actual amount in the account - Monthly fee - Overdraft protection fee - Check written + Amount transferred ............ (1)

Substituting all the relevant values into equation (1), we have:

Balance on statement = $256 - $8 - $33 - $312 + $250

Balance on statement = $153

Learn more about bank statement balance here: brainly.com/question/13837329.

#SPJ1

8 0

2 years ago

Iq scores are normally distributed with a mean of 100 and a standard deviation of 15.

bearhunter [10]

Mean is $\mu=100$ and a standard deviation is $\sigma =15$ , then the variable $X\sim N(100,15^2)$ .

Use substitution

$Z=\dfrac{X-\mu}{\sigma},\\ \\ Z=\dfrac{X-100}{15}$ .

This substitution gives you that $Z\sim N(0,1)$ .

a. For X=130, $Z=\dfrac{130-100}{15}=2$ and $Pr(X>130)=Pr(Z>2) =0.9772$ (the decimal value is taken from the Standard Normal Distribution Table).

b. For X=90, $Z=\dfrac{90-100}{15}=-\dfrac{2}{3}$ and for X=110, $Z=\dfrac{110-100}{15}=\dfrac{2}{3}$ . Then $Pr(90$ (the decimal value is taken from the Standard Normal Distribution Table).

6 0

3 years ago