1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
hodyreva [135]
2 years ago
6

Identify the 25th term of the arithmetic sequence 2, 1 and 3 over 5, 1 and 1 over 5 …

Mathematics
2 answers:
maksim [4K]2 years ago
8 0
We are given the arithmetic series 2, 1 3/5, 1 1/5.. In this case, the arithmetic difference is -2/5 by taking the difference of 2 and 1 3/5 and 1 3/5 and 1/5. The general formula of arithmetic sequence is an = a1 + d*(n-1). Substituting, an = 2 -2/5*(n-1). a25 hence is equal to a25 = 2-2/5*(25-1) = -38/5
Nookie1986 [14]2 years ago
4 0

Answer:

-7 3/5 is your CORRECT answer! Hope this helps!!

Have a good day!

You might be interested in
Community coffee company wants a new flavor of cajun coffee. how many pounds of coffee worth $7 a pound should be added to 14 po
olga_2 [115]
14x4=56
5x14=70
70-56=14
14/7=2
8 0
2 years ago
Help me out with this equation would be very helpful
Lisa [10]

Answer:

I think its C

Step-by-step explanation:

I could be wrong

3 0
2 years ago
Find the value of x.
kipiarov [429]
Are there multiple choice options??
8 0
2 years ago
In the year 2005 , a total of 750 fish were introduced into a manmade lake . The fish population was expected to grow at a rate
xxTIMURxx [149]

Answer:

The fish population will be in 2050 = 27,123

Step-by-step explanation:

Given,

In 2005, the total number of fish were introduced (fish population), PV = 750

The growth rate, i = 8.3% = 0.083

The difference between 2050 and 2005 is (2050 - 2005), n = 45 years

We need to solve this problem with the help of future value of compounding. We know, FV = PV (1+i)^n, where, PV = present value, i = interest rate, n = period.

Therefore, the fish population will be in 2050 = 750 x (1 + 0.083)^45

The fish population will be in 2050 = 27,123.26

2050 fish population = 27,123 (Nearest to whole number).

3 0
3 years ago
The life in hours of a thermocouple used in a furnace is known to be approximately normally distributed, with standard deviation
Effectus [21]

Answer:

62 is the minimum sample size needed

Step-by-step explanation:

We know that the population is approximately normally distributed so we will use a z-score for 95% confidence, which is 1.96.  We are given the population standard deviation of σ = 20, and are given that the error should be 5 or less hours.  The fact that it gives us sample data is irrelevant since we are told the population is approximately normally distributed and are given the population standard deviation.

See the attached photo for the calculation of the minimum sample size

8 0
2 years ago
Other questions:
  • Let's say we have a circle with a radius of 17 inches. What is the circumference of this circle in inches? Round your answer to
    14·1 answer
  • Jacob’s recipe calls for 4 7/8 cups of raisins. He has 6/11 of the amount that he needs.
    9·1 answer
  • What is 80% more than 20.00
    12·2 answers
  • Order the numbers from greatest to least 39,008; 39,801; 37,999
    9·2 answers
  • 7x+9≥2
    13·1 answer
  • The two given triangles are similar. Find the missing length y, rounding to 1 decimal place if necessary.
    10·1 answer
  • Use the correct math operation to determine the unit price (price per ounce) for the 2-liter bottle priced at $1.39. (67.6 ounce
    5·2 answers
  • A car travels 0.75 miles every minute, how could you explain how to use proportional reasoning to find how far the car travels i
    8·2 answers
  • How long is the arc intersected by a central angle of StartFraction 5 pi Over 3 EndFraction radians in a circle with a radius of
    10·1 answer
  • The radius of a circle wheel is 35 cm. How many revolutions does it make to cover a distance of 81.40
    10·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!