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3 years ago

Identify the 25th term of the arithmetic sequence 2, 1 and 3 over 5, 1 and 1 over 5 …

2 answers:

8 0

We are given the arithmetic series 2, 1 3/5, 1 1/5.. In this case, the arithmetic difference is -2/5 by taking the difference of 2 and 1 3/5 and 1 3/5 and 1/5. The general formula of arithmetic sequence is an = a1 + d*(n-1). Substituting, an = 2 -2/5*(n-1). a25 hence is equal to a25 = 2-2/5*(25-1) = -38/5

Nookie1986 [14]3 years ago

4 0

Answer:

-7 3/5 is your CORRECT answer! Hope this helps!!

Have a good day!

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Suppose that Stephen is the quality control supervisor for a food distribution company. A shipment containing many thousands of

solmaris [256]

Answer:

what subject is this in

Step-by-step explanation:

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3 years ago

1. Jackson has 75¢ in dimes, d, and nickels, n, in his pocket. Which equation could be solved to find the possible combinations

SpyIntel [72]

Answer:

Part 1) Option D $75=10d+5n$

Part 2) Option B $(4, -2), (0, -1), (-4, 0)$

Part 3) Option A $50=2LW$

Part 4) Option A Ms. Monti bought $4$ adult tickets and $3$ children’s tickets

Part 5) Option D The kitten weighed $14$ ounces when it was $4$ weeks old

Step-by-step explanation:

Part 1)

we know that

$1\ dime=\$0.10$

$1\ nickel=\$0.05$

Let

d-------> the number of dimes

n-----> the number of nickels

$0.10d+0.05n=0.75$

Multiply by $100$ both sides

$10d+5n=75$

Part 2)

we have

$y=(-\frac{1}{4})x-1$

To calculate the solutions of the equation for an x value, substitute the value of x in the equation and find the value of y

For $x=4$ -----> $y=(-\frac{1}{4})(4)-1=-2$ ----> $(4,-2)$

For $x=0$ -----> $y=(-\frac{1}{4})(0)-1=-1$ ----> $(0,-1)$

For $x=-4$ -----> $y=(-\frac{1}{-4})(4)-1=0$ ----> $(-4,0)$

Part 3)

we know that

The perimeter of a rectangle is equal to

$P=2(L+W)$

we have

$P=50\ ft$

substitute

$50=2(L+W)$ ------> $50/2=(L+W)$ -----> $50=2L+2W$

Par 4)

Let

x------> the number of adult tickets

y------> the number of children tickets

we have

$25x + 15y = 145$

The ordered pair $(4,3)$ represent

$x=4\ adult\ tickets$

$y=3\ children\ tickets$

therefore

Ms. Monti bought $4$ adult tickets and $3$ children’s tickets

Part 5)

Let

x------> the number of weeks after it was born

y-----> the kitten’s weight in ounces

we have

$y=2.5x+4$

The ordered pair $(4,14)$ represent

$x=4\ weeks$

$y=14\ ounces$

therefore

The kitten weighed $14$ ounces when it was $4$ weeks old

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3 years ago

Twelve students tried out for the cheerleading squad. Three students were selected. What is the ratio of students selected to th

dmitriy555 [2]

Answer:

1:4 I'm not sure though

4 0

3 years ago

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A pyramid has a height of 18 cm and a base with an area of 26 cm² find the volume

ch4aika [34]

Answer:

V=156cm³

Step-by-step explanation:

5 0

3 years ago

If sin theta = 8/17 and cot theta < 0, what is sec theta?

klasskru [66]

Answer:

$-\frac{17}{15}$

Step-by-step explanation:

By definition, $\cot \theta=\frac{1}{\tan \theta}$ and $\sec \theta=\frac{1}{\cos \theta}$ . Since since $\cot \theta$ is negative, $\tan \theta$ must also be negative, and since $\sin \theta$ is positive, we must be in Quadrant II.

In a right triangle, the sine of an angle is equal to its opposite side divided by the hypotenuse. The cosine of an angle in a right triangle is equal to its adjacent side divided by the hypotenuse. Therefore, we can draw a right triangle in Quadrant II, where the opposite side to angle theta is 8 and the hypotenuse of the triangle is 17.

To find the remaining leg, use to the Pythagorean Theorem, where $a^2+b^2=c^2$ , where $c$ is the hypotenuse, or longest side, of the right triangle and $a$ and $b$ are the two legs of the right triangle.

Solving, we get:

$8^2+b^2=17^2,\\b^2=17^2-8^2,\\b^2=\sqrt{17^2-8^2}=\sqrt{225}=15$

Since all values of cosine theta are negative in Quadrant II, all values of secant theta must also be negative in Quadrant II.

Thus, we have:

$\sec\theta=\frac{1}{\cos \theta}=-\frac{1}{\frac{15}{17}}=\boxed{-\frac{17}{15}}$

6 0

3 years ago