Hi, your question was incomplete hence I have attached the complete version of the question below.
Answer:
<u>5x^3 y^2</u>
Step-by-step explanation:
Using the property of the product of the exponents on the base and removing the parentheses,
(125x^9y^6)^(1/3) = (125)^(1/3) * (x^9)^(1/3) * (y^6)^(1/3)
= (125)^(1/3) * (x)^9*(1/3) * (y)^6*(1/3)
= 5 * (x)^3 * (y)^2
= 5 x^3 y^2
hence the required result is 5 x^3 y^2
Answer:
3,600
Step-by-step explanation:
(22 - 2) x 180
20 x 180
3,600
Student 1 was correct. When compass is placed at M and width is adjusted to L, that distance between M and L corresponds to the angle ∠LQM. Therefore the distance between L and M should be equal to the distance between N and point T which is to be constructed. IF the distance LM = NT then the angles ∠LQM and ∠NPT are equal . these are corresponding angles which means that PT and QR are parallel.
PT straight segment is extended. Since opposite sides in a rhombus should be equal, the compass width is adjusted to QR and compass is placed on P to mark the distance of where point S will line on the extended PT line. This is so that PS = QR.
hence, a line PS is drawn that is parallel to QR and equal in length
Answer:
B
Step-by-step explanation:
∠ACE and ∠ECB form a straight angle whose sum = 180°, hence
2x + 2 + 5x + 3 = 180
7x + 5 = 180 ( subtract 5 from both sides )
7x = 175 ( divide both sides by 7 )
x = 25 → C
Answer:
Answer Choice 'A' would be correct.
