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3 years ago

An approximate solution to an equation is found using this iterative process

Mathematics

1 answer:

garik1379 [7]3 years ago

8 0

Answer:

a)(i)x2= -0.5

b)(ii)x3= -0.28125

Step-by-step explanation:

Sorry But I cannot explain the working out.

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BIG POINTS Please solve. Thanks!

Nitella [24]

9^1/3 * 3^x = 27^4/5

Rewrite 9 as 3^2

(3^2)^1/3 * 3^x = 27^4/5

Multiply the exponents in the first term:

3^2/3 * 3^x = 27^4/5

Use power rule to combine exponents:

3^(2/3 +x) = 27^4/5

Rewrite the 2nd term:

3^(2/3 +x) = (3^3)^4/5

Set the exponents only to equal:

2/3 + x = 3(4/5)

Solve for x:

simplify the right side:

2/3 + x = 12/5

Subtract 2/3 from both sides:

x = 26/15

3 0

3 years ago

Solve for p: p – 23 = -3 A. p = 20 B. p = -20 C. p = -26 D. p = 69

Alekssandra [29.7K]

P-23=-3
+23 +23

P=20

so the answer is A

6 0

2 years ago

PLEASE HELP !! ILL GIVE BRAINLIEST !!

CaHeK987 [17]

Answer:

1 and 4, 2 and 3, 5 and 8, 6 and 7

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

Solve the equation for x: -3(x + 4) + 5x = 24

mr_godi [17]

<h2>Answer:</h2>

$-3(x + 4) + 5x = 24\\\\-3x - 12 + 5x = 24\\\\2x - 12 = 24\\\\2x = 36\\\\x = 18$

The solution for x in this equation is 18.

6 0

2 years ago

Read 2 more answers

If tan ⁡x=12/5, and 0°

Charra [1.4K]

The value of sin(2x) is $\frac{120}{169}$

Explanation:

Given that $tan x =\frac{12}{5}$

The formula for $sin(2x)$ is $\sin (2 x)=2 \sin x \cos x$

Since, $\tan x=\frac{o p p}{a d j}$

Also, it is given that $tan x =\frac{12}{5}$

Thus, $opp=12$ and $adj=5$

To find the hypotenuse, let us use the pythagoras theorem,

$\begin{aligned}h y p &=\sqrt{12^{2}+5^{2}} \\&=\sqrt{144+25} \\&=\sqrt{169} \\&=13\end{aligned}$

Now, we can find the value of sin x and cos x.

$\sin x=\frac{\text { opp }}{h y p}=\frac{12}{13}$

$\cos x=\frac{a d j}{h y p}=\frac{5}{13}$

Now, substituting these values in the formula for sin 2x, we get,

$\begin{aligned}\sin (2 x) &=2 \sin x \cos x \\&=2\left(\frac{12}{13}\right)\left(\frac{5}{13}\right) \\&=\frac{120}{169}\end{aligned}$

Thus, the value of sin(2x) is $\frac{120}{169}$

8 0

3 years ago