d = 3 , a₁₂ = 40 and S
= 7775
In an arithmetic sequence the nth term and sum to n terms are
<h3>• a
= a₁ + (n-1)d</h3><h3>• S
=
[2a + (n-1)d]</h3><h3>
where d is the common difference</h3><h3>a₆ = a₁ + 5d = 22 ⇒ 7 + 5d = 22 ⇒ 5d = 15 ⇔ d = 3</h3><h3>a₁₂ = 7 + 11d = 7 +( 11× 3) = 7 + 33 = 40</h3><h3>S₁₀₀ =
[(2×7) +(99×3)</h3><h3> = 25(14 + 297) = 25(311)= 7775</h3>
Answer:
answer below
Step-by-step explanation:
ABCDE go through dilation over center (6 , -2) with factor of 1/2 to FGHIJ
AB // FG slope: -2 , √20:√5 = 2: 1
BC // GH // X axis 8:4 = 2:1
CD // HI, slope= 1 , √8:√2 = 2:1
DE // IJ // x axis, 4:2 = 2:1
EA // JF // y axis, 2:1
The answer is d because the line is cutting thru the x axis on 1/3 and then the line cuts thru the y axis on -2 so the answer would be 1/3x-2
Answer:
y=5x + 21
Step-by-step explanation:
y=5x×b
6= -15+b
b=21
The answer is 0, as there is no slope going up or down.
