(pls help!!) Find an equation in point-slope form for the line having the slope m=2 and containing the point (4,5).

A nurse is investigating the birth weights of non-premature babies. She selects a random sample of 41 such babies, and found a

kherson [118]

Answer:

The 95% confidence interval for the mean birth weight of all non-premature babies is between 3350.4 grams and 3662.4 grams. This means that we are 95% sure that true mean birth weight of all non-premature babies is in this interval.

Step-by-step explanation:

We have the standard deviation for the sample, which means that the t-distribution is used to solve this question.

The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So

df = 41 - 1 = 40

95% confidence interval

Now, we have to find a value of T, which is found looking at the t table, with 40 degrees of freedom(y-axis) and a confidence level of $1 - \frac{1 - 0.95}{2} = 0.975$ . So we have T = 2.0211

The margin of error is:

$M = T\frac{s}{\sqrt{n}} = 2.0211\frac{494.2}{\sqrt{41}} = 156$

In which s is the standard deviation of the sample and n is the size of the sample.

The lower end of the interval is the sample mean subtracted by M. So it is 3506.4 - 156 = 3350.4 grams

The upper end of the interval is the sample mean added to M. So it is 3506.4 + 156 = 3662.4 grams

The 95% confidence interval for the mean birth weight of all non-premature babies is between 3350.4 grams and 3662.4 grams. This means that we are 95% sure that true mean birth weight of all non-premature babies is in this interval.

6 0

3 years ago

What is (-8)(-8)(-1)?

VMariaS [17]

-64, using the negative times negative equals positive and negative times anything else = negative rule, you get -64

3 0

3 years ago

Read 2 more answers

Solve the equation 7z=105

zmey [24]

The answer is 15 because u divide 7 on both sides

4 0

3 years ago

If your starting salary is 40,000 and you receive a 3% increase at the end of every year, what is the total amount, in dollars,

liberstina [14]

$\bf \qquad \textit{Amount for Exponential Growth}\\\\
A=I(1 + r)^t\qquad 
\begin{cases}
A=\textit{accumulated amount}\\
I=\textit{initial amount}\to &40,000\\
r=rate\to 3\%\to \frac{3}{100}\to &0.03\\
t=\textit{elapsed time}\to &16\\
\end{cases}
\\\\\\
A=40000(1+0.03)^{16}\implies A=40000(1.03)^{16}$

5 0

3 years ago

Read 2 more answers

Which line is a linear model for the data?

olga2289 [7]

Answer:

Your selected answer is correct.

Step-by-step explanation:

As you can see, the line and the points given follow the same vague path, while the others are below it for the most part, or going the wrong direction.

8 0

2 years ago