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Ksenya-84 [330]
3 years ago
7

I give brainliest !

Mathematics
1 answer:
gladu [14]3 years ago
8 0

Answer:

I can't be sure.

Step-by-step explanation:

I can't be sure if this image is to scale or not, there is no marker indicating the distance.

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Find the sell tax to complete the table
poizon [28]
The answer would be $3.2
Do ya want me to explain my answer
4 0
3 years ago
The Center for Medicare and Medical Services reported that there were 295,000 appeals for hospitalization and other Part A Medic
Ymorist [56]

Answer:

(a) 0.00605

(b) 0.0403

(c) 0.9536

(d) 0.98809

Step-by-step explanation:

We are given that 40% of first-round appeals were successful (The Wall Street Journal, October 22, 2012) and suppose ten first-round appeals have just been received by a Medicare appeals office.

This situation can be represented through Binomial distribution as;

P(X=r)= \binom{n}{r}p^{r}(1-p)^{n-r} ; x = 0,1,2,3,....

where,  n = number of trials (samples) taken = 10

            r = number of success

            p = probability of success which in our question is % of first-round

                   appeals that were successful, i.e.; 40%

So, here X ~ Binom(n=10,p=0.40)

(a) Probability that none of the appeals will be successful = P(X = 0)

     P(X = 0) = \binom{10}{0}0.40^{0}(1-0.40)^{10-0}

                   = 1*0.6^{10} = 0.00605

(b) Probability that exactly one of the appeals will be successful = P(X = 1)

     P(X = 1) = \binom{10}{1}0.40^{1}(1-0.40)^{10-1}

                  = 10*0.4^{1} *0.6^{10-1} = 0.0403

(c) Probability that at least two of the appeals will be successful = P(X>=2)

    P(X >= 2) = 1 - P(X = 0) - P(X = 1)

                     = 1 - \binom{10}{0}0.40^{0}(1-0.40)^{10-0} - \binom{10}{1}0.40^{1}(1-0.40)^{10-1}

                     = 1 - 0.00605 - 0.0403 = 0.9536

(d) Probability that more than half of the appeals will be successful =             P(X > 0.5)

  For this probability we will convert our distribution into normal such that;

   X ~ N(\mu = n*p=4,\sigma^{2}= n*p*q = 2.4)

  and standard normal z has distribution as;

      Z = \frac{X-\mu}{\sigma} ~ N(0,1)

  P(X > 0.5) = P( \frac{X-\mu}{\sigma} > \frac{0.5-4}{\sqrt{2.4} } ) = P(Z > -2.26) = P(Z < 2.26) = 0.98809

3 0
3 years ago
A student is running a 3-kilometer race. He runs 1 kilometer every 2 minutes. Select the function that describes his distance fr
Ronch [10]

Answer:x - number of minutes;

f ( x ) - the distance from the finish line.

  x :        0     2      4      6

f ( x ) :    3      2      1     0

f ( x ) = 3 - x/2

Answer: B ) f ( x ) = -1/2 x + 3

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
Hi please help me really need it!
adelina 88 [10]

Answer:

C

Step-by-step explanation:

To Solve, just cube the terms on the right side to see if they go back to the number on the left.

The first part is true because multiplying 11 * 11 * 11 = 1331.

The second part is true because multiplying 5 * 5* 5 = 125.

The third part is false because multiplying 8 * 8 * 8 = 512.

The fourth part is true because multiplying 1 * 1* 1 = 1.

8 0
3 years ago
The percentage of U.S. college freshmen claiming no religious affiliation has risen in recent decades. The bar graph shows the
emmainna [20.7K]

Answer:

0.5%/year

24.2%

Step-by-step explanation:

Estimate the average yearly increase in the percentage of first-year college females claiming no religious affiliation

Percentage of females by year:

1980 = 6.2%

1990 = 10.8%

2000 = 13.6%

2012 = 21.7%

Average yearly increase :

Percentage increase between 1980 - 2012 :

2012% - 1980% = ( 21.7% - 6.2%) = 15.5% increase over [(2012 - 1980)] = 32 years

15.5 % / 32 years = 0.484375% / year = 0.5%/year

b. Estimate the percentage of first-year college females who will claim no religious affiliation in 2030,

Given an average increase of 0.484375% / year

(2030 - 1980) = 50 years

Hence by 2030 ; ( 50 years × 0.484375%/year) = 24.218% will claim no religious affiliation.

=24.2% (nearest tenth)

3 0
4 years ago
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