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larisa86 [58]
3 years ago
8

What is the ratio of 1/5 to 5/15 ?help​

Mathematics
2 answers:
Annette [7]3 years ago
5 0

Answer:

15:25 is the ratio

Step-by-step explanation:

1/5 to 5/15

(1/5)/(5/15)

15:25

So 15:25 is the answer

timama [110]3 years ago
3 0
1/5:1/3? I’m not sure..
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Subtract 5x^2-2x-55x 2 −2x−5 from -2x^2-5x-7−2x 2 −5x−7.
leva [86]

Answer:

7x^2 -128x -19

Step-by-step explanation:

5 0
2 years ago
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HELP PLZ!! Convert 80 mph (miles per hour) to feet per second.
marin [14]

Answer:

117.33333 feet per second

Step-by-step explanation:

6 0
2 years ago
The cost for two different companies to make x candles is shown on the graph.
tia_tia [17]

Answer:

D) Quick Wick will make more candles when the cost is $600.

Step-by-step explanation:

Find the initial value (b) and the cost per candle (m), to write the equation of each line in the slope-intercept form, y = mx + b. This will help for easy comparison.

✔️Wax Art:

m = change in y/change in x

Using (10, 140) and (20, 180),

m = (180 - 140)/(20 - 10) = 40/10

m = 4

Cost per candle = $4

To find b, substitute (x, y) = (10, 140) and m = 4 into y = mx + b

140 = 4(10) + b

140 = 40 + b

140 - 40 = b

100 = b

b = 100

Initial value = $100

To get the equation, substitute m = 4 and b = 100 into y = mx + b

y = 4x + 100

✔️Quick Wick:

m = change in y/change in x

Using (10, 120) and (30, 180),

m = (180 - 120)/(30 - 10) = 60/20

m = 3

Cost per candle = $3

To find b, substitute (x, y) = (10, 120) and m = 3 into y = mx + b

120 = 3(10) + b

140 = 30 + b

120 - 30 = b

90 = b

b = 90

Initial value = $90

To get the equation, substitute m = 3 and b = 90 into y = mx + b

y = 3x + 90

Let's analyse each option given using the information we now have:

✔️Option A: INCORRECT

Cost per candle for made is $1 less for Quick Wick. I.e. cost per candle for Quick wick is $3. Cost per candle for Wax Art is $4.

✔️Option B: INCORRECT

Difference between the initial value sof the two companies = $100 - $90 = $10

✔️Option C:

Find the cost of making 50 candles for each company by substituting x = 50 into each of their equations. Thus:

Wax Art => y = 4x + 100

y = 4(50) + 100

y = $300

Wax Art will make 50 candles for $300

Quick Wick => y = 3x + 90

y = 3(50) + 90

y = $240

Quick Wick makes 50 candles for $240

As we can see, Quick wick is making 50 candles at a lower cost than Wax Art.

Therefore, option C is INCORRECT.

✔️Option D: find out how many candles (x) each company will make when the cost is $600.

Substitute y = 600 in each equation of both companies

Wax Art => y = 4x + 100

600 = 4x + 100

600 - 100 = 4x

500 = 4x

500/4 = x

x = 125 candles

Quick Wick => y = 3x + 90

600 = 3x + 90

600 - 90 = 3x

510 = 3x

510/3 = x

x = 170 candles

Quick Wick will make more candles when he cost is $600.

Therefore, option D is the only CORRECT statement of comparison.

6 0
2 years ago
Mr. Flores has 100 pictures in a photo album. Of these pictures, 20 show his friends, 50 show his family, and 30 show his pet da
saw5 [17]

Answer:

false

Step-by-step explanation:

just trust me

8 0
2 years ago
How do you find a vector that is orthogonal to 5i + 12j ?
Rashid [163]
\bf \textit{perpendicular, negative-reciprocal slope for slope}\quad \cfrac{a}{b}\\\\
slope=\cfrac{a}{{{ b}}}\qquad negative\implies  -\cfrac{a}{{{ b}}}\qquad reciprocal\implies - \cfrac{{{ b}}}{a}\\\\
-------------------------------\\\\

\bf \boxed{5i+12j}\implies 
\begin{array}{rllll}
\ \textless \ 5&,&12\ \textgreater \ \\
x&&y
\end{array}\quad slope=\cfrac{y}{x}\implies \cfrac{12}{5}
\\\\\\
slope=\cfrac{12}{{{ 5}}}\qquad negative\implies  -\cfrac{12}{{{ 5}}}\qquad reciprocal\implies - \cfrac{{{ 5}}}{12}
\\\\\\
\ \textless \ 12, -5\ \textgreater \ \ or\ \ \textless \ -12,5\ \textgreater \ \implies \boxed{12i-5j\ or\ -12i+5j}

if we were to place <5, 12> in standard position, so it'd be originating from 0,0, then the rise is 12 and the run is 5.

so any other vector that has a negative reciprocal slope to it, will then be perpendicular or "orthogonal" to it.

so... for example a parallel to <-12, 5> is say hmmm < -144, 60>, if you simplify that fraction, you'd end up with <-12, 5>, since all we did was multiply both coordinates by 12.

or using a unit vector for those above, then

\bf \textit{unit vector}\qquad \cfrac{\ \textless \ a,b\ \textgreater \ }{||\ \textless \ a,b\ \textgreater \ ||}\implies \cfrac{\ \textless \ a,b\ \textgreater \ }{\sqrt{a^2+b^2}}\implies \cfrac{a}{\sqrt{a^2+b^2}},\cfrac{b}{\sqrt{a^2+b^2}}&#10;\\\\\\&#10;\cfrac{12,-5}{\sqrt{12^2+5^2}}\implies \cfrac{12,-5}{13}\implies \boxed{\cfrac{12}{13}\ ,\ \cfrac{-5}{13}}&#10;\\\\\\&#10;\cfrac{-12,5}{\sqrt{12^2+5^2}}\implies \cfrac{-12,5}{13}\implies \boxed{\cfrac{-12}{13}\ ,\ \cfrac{5}{13}}
4 0
3 years ago
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