Question

What is the distance between the points (2 and one-half, negative 8) and (2 and one-half, 3) Sukant’s work is shown below?

Answer 1

Given Information:

Point 1 = ( 2½, -8)

Point 2 = ( 2½, 3)

Required Information:

Distance between two points = d = ?

Answer:

Distance between two points = $d = 11$ $units$

Step-by-step explanation:

The distance between two points is calculated using

$d = \sqrt{(x_{2} - x_{1})^2 + (y_{2} - y_{1})^2}$   eq. 1

We have (x₁, y₁) = (2½, -8) and (x₂, y₂) = (2½, 3)

Substitute the above points into the eq. 1

$d = \sqrt{(2\textonehalf - 2\textonehalf)^2 + (3 - (-8))^2}$

$d = \sqrt{(2\textonehalf - 2\textonehalf)^2 + (3 + 8)^2}$

$d = \sqrt{(0)^2 + (11)^2}$

$d = \sqrt{0 + 121}$

$d = \sqrt{121}$

$d = 11$ $units$

it is very unclear as what error did Sukant make due to unclear typing!

But I guess, Sukant simply added the x-coordinates together that is

d = 2½ + 2½ = 5 units

Note: 2½ = 5/2 = 2.5

Answer 2

Answer:

He should have used the y-coordinates

Step-by-step explanation:

I don't have one.