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iren2701 [21]
2 years ago
6

What is the quotient of 1+ 3 Over 4 and 2 over 5

Mathematics
1 answer:
dolphi86 [110]2 years ago
5 0

Answer:

2 1/2

Step-by-step explanation:

(These are fractions)

1+3 ÷ 2

4 5

(Simplify)

4 ÷ 2

4 5

(Same denominator)

20 ÷ 8

20 20

(Divide)

2 1/2

You might be interested in
PLEASE HELP!!!!!!!!!!!!1
skelet666 [1.2K]
A. Let x = cheese and
y = chocolate
2x + y = 25
x + y = 20

B. Subtract the second equation from the first.
2x + y = 25
-(x + y = 20)
-—————
x = 5

Plug 5 back in to the second equation and solve for y.
x + y = 20
5 + y = 20
Subtract 5 from both sides.
y = 15
5 cheese and 15 chocolate

Used elimination method because coefficients on the y values were both 1 so it was easy to subtract the equations and eliminate the y variable.


5 0
3 years ago
How does 15.050 compare to 15.500
Varvara68 [4.7K]

15.050 < 15.500

notice that 500 is more than 50... so hope this helps a little bit !!!

:)

6 0
3 years ago
Read 2 more answers
Please help I will make you the brainiest (please no link people)
Andre45 [30]

Answer:

Solution,

Radius(r)=6 cm

Height(h)=20 cm

Volume of cylinder= pi (r)^2 h

=3.14*(6)^2*20

=3.14*36*20

=2260.8 cm^3

Hope it helps

Good luck on your assignment

4 0
2 years ago
One Solution<br> 6-3+4x+1=
Volgvan

+4x +2 = 0

4x = -2

x = -0.5 = -1/2

6 0
2 years ago
Read 2 more answers
Find the domain over which the function y = x + 6x is monotonic increasing.
iragen [17]

Answer:

x > -3

\sf (-3, \infty)

Step-by-step explanation:

Domain: input values (x-values)

Monotonic increasing:  always increasing.  
A function is increasing when its graph rises from left to right.

The graph of a quadratic function is a parabola.  If the leading term is positive, the parabola opens upwards.  The domain over which the function is increasing for a parabola that opens upwards is values greater than the x-value of the vertex.

<u>Vertex</u>

Standard form of quadratic equation:  \sf y=ax^2+bx+c

\textsf{x-value of vertex}=\sf -\dfrac{b}{2a}

Given function:

\sf y=x^2+6x

Therefore, x-value of function's vertex:

\sf \implies x= -\dfrac{6}{2}=-3

<u>Final Solution</u>

The function is increasing when x > -3

\sf (-3, \infty)

4 0
2 years ago
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