Answer:
B
Step-by-step explanation:

Answer:
see attached diagram
Step-by-step explanation:
First, draw the dashed line 50x+150y=1500 (dashed because the inequality is without notion "or equal to"). You can do it finding x and y intercepts.
When x=0, then 150y=1500, y=10.
When y=0, then 50x=1500, x=30.
Connect points (0,10) and (30,0) to get needed dashed line.
Then determine which region (semiplane) you have to choose. Note that origin's coordinates (0,0) do not satisfy the inequality 50x + 150y>1500, because

This means that origin lies outside the needed region, so you have to choose the semiplane that do not contain origin (see attached diagram).
Answer: 2y+6
Step-by-step explanation:
Answer: No es posible (It is not possible)
Step-by-step explanation:
The question in english is as follows:
Is it possible to draw 9 line segments so that each segment crosses exactly 1 of the other segments?
A necessary condition for two lines to intersect is that they must be in the same plane (they must be coplanar), being their intersection a single point.
Now, if we want several lines to intersect only once, we need to have an <u>even number</u> of line segments. However, this is not the case because <u>9 is odd.
</u>
Therefore, it is not possible.