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WARRIOR [948]
3 years ago
5

Find each absolute value| 4+2i || 5-i || -3i |

Mathematics
2 answers:
GrogVix [38]3 years ago
8 0

Well it would stay the same since you need to have i to equal something

galina1969 [7]3 years ago
4 0

How to get answer for number 1: | 4+2i |

\left|a+bi\right|\:=\sqrt{\left(a+bi\right)\left(a-bi\right)}=\sqrt{a^2+b^2}\\\mathrm{With\:}a=4,\:b=2\\=\sqrt{4^2+2^2}\\Refine\\=\sqrt{20}\\\sqrt{20}=2\sqrt{5}\\=2\sqrt{5}

How to get answer for number 2: | 5-i |

\left|a+bi\right|\:=\sqrt{\left(a+bi\right)\left(a-bi\right)}=\sqrt{a^2+b^2}\\\mathrm{With\:}a=5,\:b=-1\\=\sqrt{5^2+\left(-1\right)^2}\\=\sqrt{26}

Number 3 how to get answer: | -3i |

\left|a+bi\right|\:=\sqrt{\left(a+bi\right)\left(a-bi\right)}=\sqrt{a^2+b^2}\\\mathrm{With\:}a=0,\:b=-3\\=\sqrt{0^2+\left(-3\right)^2}\\Refine\\=\sqrt{9}\\\sqrt{9}\\\mathrm{Factor\:the\:number:\:}\:9=3^2\\=\sqrt{3^2}\\\mathrm{Apply\:radical\:rule}:\quad \sqrt[n]{a^n}=a\\\sqrt{3^2}=3\\= 3

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3 years ago
Add or Subtract to Simplify:<br> (x5 + x3) - (6x - x3 + 6x5)
ziro4ka [17]

Answer:

\boxed{ \bold{   \boxed{ \sf{ - 5 {x}^{5}  + 2 {x}^{3}  - 6x}}}}

Step-by-step explanation:

\sf{( {x}^{5}  +  {x}^{3} ) - (6x -  {x}^{3}  + 6 {x}^{5}) }

When there is a ( - ) in front of an expression in parentheses , change the sign of each term.

Also, remove the parentheses

⇒\sf{ {x}^{5}  +  {x}^{3}  - 6x +  {x}^{3}  - 6 {x}^{5} }

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3 0
2 years ago
The weight of an object on mars varies directly is proportional as the weight of the object on earth a 75 pound object on earth
dedylja [7]

Answer:

It weighs 40 pounds on mars

Step-by-step explanation:

Direct proportion is the relationship between two variables when their ratio is equal to a constant value

  • It can be expressed as y = k x, where y varies directly as x and k is constant of variation
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∵ The weight of an object on mars varies directly as the weight

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∴ w(m) = k × w(e)

∵ The weight of the object on earth is 75 pound

∴ w(e) = 75

∵ The weight of this object on mars is 25 pounds

∴ w(m) = 25

- Substitute them in the equation of variation

∵ 25 = k × 75

- Divide both sides by 75

∴ \frac{1}{3} = k

∴ w(m) = \frac{1}{3} × w(e)

∵ An object weighs 120 pounds on earth

∴ w(e) = 120

- Substitute it in the equation of variation

∴ w(m) = \frac{1}{3} × 120

∴ w(m) = 40

∴ It weighs 40 pounds on mars

5 0
3 years ago
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